Algebra 1 · Unit 1
Turn a sentence into an equation in one variable.
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Name the variable first
Say what the letter stands for before you write the math. Include units when the story has them (hours, dollars, tickets, gallons).
Translate the words
is / equals → =. Write the same value on both sides.
sum, increased by, more than, plus → add. difference, decreased by, less than, minus → subtract.
product, times, of, twice → multiply. quotient, divided by, half of → divide.
squared is n². cubed is n³.
Order matters when you subtract
“5 less than n” is n − 5, not 5 − n.
“the difference of n and 5” is n − 5. “the difference of 5 and n” is 5 − n.
Starting amount and a rate
Increasing: (amount) = (start) + (rate)(quantity).
Decreasing: (amount) = (start) − (rate)(quantity). The rate is the number that multiplies the variable.
Perimeter of a rectangle
Write one side in terms of the other, then use P = 2ℓ + 2w.
Substitute the expressions for the sides. Do not plug in a guessed number for ℓ or w.
Consecutive integers
Consecutive integers differ by 1: n and n + 1. Three in a row: n, n + 1, n + 2.
Consecutive even integers and consecutive odd integers both differ by 2: n and n + 2. Three in a row: n, n + 2, n + 4.
One sentence. Name the variable, then write the equation.
“9 more than n” is n + 9.
is means =.
n + 9 = 24
Answer: n + 9 = 24
The sum of n and 17 is n + 17.
n + 17 = 41
Answer: n + 17 = 41
The difference of n and 38 is n − 38.
n − 38 = 11
Answer: n − 38 = 11
The quotient of n and 7 is n7.
n7 = 8
Answer: n7 = 8
n decreased by 15 is n − 15.
n − 15 = 22
Answer: n − 15 = 22
Half of n is n2.
n2 = 16
Answer: n2 = 16
n increased by 9 is n + 9.
n + 9 = 31
Answer: n + 9 = 31
The product of n and 9 is 9n.
9n = 72
Answer: 9n = 72
n squared is n².
n² = 81
Answer: n² = 81
Twice n is 2n.
2n = 28
Answer: 2n = 28
The quotient of 42 and n is 42n.
42n = 6
Answer: 42n = 6
n cubed is n³.
n³ = 64
Answer: n³ = 64
8 subtracted from n is n − 8.
n − 8 = 19
Answer: n − 8 = 19
Four times n is 4n.
Increased by 7 is 4n + 7.
4n + 7 = 35
Answer: 4n + 7 = 35
Five times n is 5n.
9 subtracted from that is 5n − 9.
5n − 9 = 16
Answer: 5n − 9 = 16
The sum of 10 and 5 is 10 + 5.
The difference of n and 8 is n − 8.
10 + 5 = n − 8
Answer: 10 + 5 = n − 8
Three times n is 3n.
The sum of that and 6 is 3n + 6.
3n + 6 = 27
Answer: 3n + 6 = 27
Twice n is 2n.
The sum of that and 11 is 2n + 11.
2n + 11 = 29
Answer: 2n + 11 = 29
Seven times n is 7n.
Decreased by 4 is 7n − 4.
7n − 4 = 38
Answer: 7n − 4 = 38
Twice n is 2n. Three times n is 3n.
Their sum is 2n + 3n.
5 added to that is 5 + (2n + 3n).
5 + (2n + 3n) = 35
Answer: 5 + (2n + 3n) = 35
3 times n is 3n.
8 less than that is 3n − 8.
3n − 8 = 19
Answer: 3n − 8 = 19
of means multiply.
35n = −9
Answer: 35n = −9
two tenths less than 3.5 is 3.5 − 210.
n = 3.5 − 210
Answer: n = 3.5 − 210
of means multiply.
410n = 1.6
Answer: 410n = 1.6
2 times n is 2n.
The difference of 2n and 13 is 2n − 13.
2n − 13 = 56
Answer: 2n − 13 = 56
The product of n and 1.5 is 1.5n.
1.5n = 6
Answer: 1.5n = 6
38 added to n is n + 38.
n + 38 = 2
Answer: n + 38 = 2
The product of 3.2 and 4.5 is 3.2 × 4.5.
n times 0.8 is 0.8n.
3.2 × 4.5 = 0.8n
Answer: 3.2 × 4.5 = 0.8n
Linear situations. The amount can increase or decrease at a constant rate.
Let h = the number of hours.
Let C = the total cost in dollars.
Start plus rate times hours.
C = 20 + 8h
Answer: C = 20 + 8h
Let h = the number of hours.
Let C = the total cost in dollars.
C = 9 + 4h
Answer: C = 9 + 4h
Let w = the number of weeks.
Let S = the amount in dollars.
S = 125 + 15w
Answer: S = 125 + 15w
Let t = the number of hours.
Let D = the total distance in miles.
D = 4 + 3t
Answer: D = 4 + 3t
Let m = the number of minutes.
Let A = the amount of water in gallons.
A = 80 + 6m
Answer: A = 80 + 6m
Let t = the number of minutes.
Let P = the total number of pages.
P = 25 + 12t
Answer: P = 25 + 12t
Let m = the number of miles.
Let C = the cost in dollars.
C = 2.75 + 0.90m
Answer: C = 2.75 + 0.90m
Let t = the number of minutes.
Let A = the amount of water in gallons.
A = 64 − 5t
Answer: A = 64 − 5t
Let h = the number of hours.
Let H = the height in inches.
H = 12 − 0.6h
Answer: H = 12 − 0.6h
Let d = the number of days.
Let B = the balance in dollars.
B = 420 − 24d
Answer: B = 420 − 24d
Let t = the number of minutes.
Let H = the height in feet.
H = 1800 − 60t
Answer: H = 1800 − 60t
Write a side in terms of the other, then use the perimeter formula.
Length = w + 5
Perimeter formula.
P = 2ℓ + 2w
Substitute.
38 = 2(w + 5) + 2w
Answer: 38 = 2(w + 5) + 2w
Width = ℓ − 6
Perimeter formula.
P = 2ℓ + 2w
Substitute.
56 = 2ℓ + 2(ℓ − 6)
Answer: 56 = 2ℓ + 2(ℓ − 6)
Length = 2w + 4
Perimeter formula.
P = 2ℓ + 2w
Substitute.
62 = 2(2w + 4) + 2w
Answer: 62 = 2(2w + 4) + 2w
Length = 3w
Perimeter formula.
P = 2ℓ + 2w
Substitute.
48 = 2(3w) + 2w
Answer: 48 = 2(3w) + 2w
Length = w + 7
Perimeter formula.
P = 2ℓ + 2w
Substitute.
50 = 2(w + 7) + 2w
Answer: 50 = 2(w + 7) + 2w
Width = ℓ + 2
Perimeter formula.
P = 2ℓ + 2w
Substitute.
40 = 2ℓ + 2(ℓ + 2)
Answer: 40 = 2ℓ + 2(ℓ + 2)
Consecutive integers differ by 1. Consecutive even integers and consecutive odd integers differ by 2.
Consecutive integers differ by 1.
The integers are n and n + 1.
n + (n + 1) = 39
Answer: n + (n + 1) = 39
Consecutive integers differ by 1.
The integers are n and n + 1.
n + (n + 1) = 61
Answer: n + (n + 1) = 61
The integers are n, n + 1, and n + 2.
n + (n + 1) + (n + 2) = 96
Answer: n + (n + 1) + (n + 2) = 96
Consecutive even integers differ by 2.
The integers are n and n + 2.
n + (n + 2) = 94
Answer: n + (n + 2) = 94
Consecutive odd integers differ by 2.
The integers are n and n + 2.
n + (n + 2) = 48
Answer: n + (n + 2) = 48
Consecutive even integers differ by 2.
The integers are n, n + 2, and n + 4.
n + (n + 2) + (n + 4) = 84
Answer: n + (n + 2) + (n + 4) = 84
Consecutive odd integers differ by 2.
The integers are n, n + 2, and n + 4.
n + (n + 2) + (n + 4) = 69
Answer: n + (n + 2) + (n + 4) = 69
Let n = the larger integer.
The smaller integer is n − 1.
(n − 1) + n = 55
Answer: (n − 1) + n = 55
Let t = the number of hours from the start.
Total cost = (cost of the first 4 hours) + (new rate)(hours after 4).
The first 4 hours cost $100. After that, the rate is $20 per hour.
t starts at the beginning, so the hours at $20 are t − 4.
100 + 20(t − 4) = 180
Answer: 100 + 20(t − 4) = 180
Let t = the number of hours from the start.
Total cost = (cost of the first 3 hours) + (new rate)(hours after 3).
The first 3 hours cost $18. After that, the rate is $6 per hour.
t starts at the beginning, so the hours at $6 are t − 3.
18 + 6(t − 3) = 54
Answer: 18 + 6(t − 3) = 54
Let t = the number of hours from the start.
Total cost = (cost of the first 2 hours) + (new rate)(hours after 2).
The first 2 hours cost $45. After that, the rate is $12 per hour.
t starts at the beginning, so the hours at $12 are t − 2.
45 + 12(t − 2) = 105
Answer: 45 + 12(t − 2) = 105
Let t = the number of hours from the start.
Total cost = (cost of the first 5 hours) + (new rate)(hours after 5).
The first 5 hours cost $80. After that, the rate is $25 per hour.
t starts at the beginning, so the hours at $25 are t − 5.
80 + 25(t − 5) = 230
Answer: 80 + 25(t − 5) = 230
Let t = the number of days from the start.
Total cost = (cost of the first 3 days) + (new rate)(days after 3).
The first 3 days cost $240. After that, the rate is $70 per day.
t starts at the beginning, so the days at $70 are t − 3.
240 + 70(t − 3) = 590
Answer: 240 + 70(t − 3) = 590
Let c = the number of croissants.
Blueberry muffins: 2c
Cinnamon rolls: c − 10
Croissants + blueberry muffins + cinnamon rolls = 85.
c + 2c + (c − 10) = 85
4c − 10 = 85
Answer: 4c − 10 = 85
Let r = the number of roses.
Tulips: 3r
Daisies: r − 8
Roses + tulips + daisies = 92.
r + 3r + (r − 8) = 92
5r − 8 = 92
Answer: 5r − 8 = 92
Let p = the number of palette knives.
8-inch is the length of each bamboo brush. The number of brushes is 3p.
4-inch is the length of each detailing pen. The number of pens is p + 5.
Palette knives + bamboo brushes + detailing pens = 40.
p + 3p + (p + 5) = 40
5p + 5 = 40
Answer: 5p + 5 = 40
Let n = the number of cones.
15-foot is the length of each agility ladder. The number of ladders is 2n.
6-inch is the height of each hurdle. The number of hurdles is n + 7.
Cones + agility ladders + hurdles = 43.
n + 2n + (n + 7) = 43
4n + 7 = 43
Answer: 4n + 7 = 43
Let g = the number of carabiners.
50-foot is the length of each rope. The number of ropes is 5g.
8-inch is the length of each stake. The number of stakes is g + 2.
Ropes + carabiners + stakes = 44.
g + 5g + (g + 2) = 44
7g + 2 = 44
Answer: 7g + 2 = 44
Let g = how many fewer garments to treat each week.
80 is the number of garments treated in a typical week. The equation uses the cost of one garment and the $6 savings.
One bottle costs $5 and treats 16 garments.
The cost of one garment is 516 dollars.
The cost of g fewer garments is the $6 the lab wants to save.
516g = 6
Answer: 516g = 6
Let v = how many fewer gallons of sap to boil each week.
90 is the number of gallons boiled in a typical week. The equation uses the cost of one gallon and the $5 savings.
One cord costs $7 and processes 20 gallons.
The cost of one gallon is 720 dollars.
The cost of v fewer gallons is the $5 the co-op wants to save.
720v = 5
Answer: 720v = 5
Let t = how many fewer meters of tubing to fill each week.
75 is the number of meters filled in a typical week. The equation uses the cost of one meter and the $4 savings.
One cylinder costs $5 and services 18 meters.
The cost of one meter is 518 dollars.
The cost of t fewer meters is the $4 the shop wants to save.
518t = 4
Answer: 518t = 4
Let w = how many fewer trays to load each week.
70 is the number of trays loaded in a typical week. The equation uses the cost of one tray and the $5 savings.
One bundle costs $3 and lasts for 14 trays.
The cost of one tray is 314 dollars.
The cost of w fewer trays is the $5 the bakery wants to save.
314w = 5
Answer: 314w = 5
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