Algebra 1 · Unit 7
Factor first- and second-degree polynomials in x and y completely.
Jump to section:
Treat y as part of the last term
x² + 5xy + 6y² is like x² + 5x + 6 with y attached to the second factor of each pair.
Multiply to the last, add to the middle
For x² + bxy + cy², find two numbers that multiply to c and add to b. Then write (x + py)(x + qy).
a > 1 still slides
Slide a onto the y² term, factor, divide, and keep y with the constants.
GCF first
2x² + 10xy + 12y² = 2(x² + 5xy + 6y²) = 2(x + 2y)(x + 3y).
a = 1. Two-variable trinomials.
Two numbers that multiply to 6 and add to 5: 2 and 3.
(x + 2y)(x + 3y)
Check: x² + 3xy + 2xy + 6y² = x² + 5xy + 6y²
Answer: (x + 2y)(x + 3y)
2 and 5
(x + 2y)(x + 5y)
Answer: (x + 2y)(x + 5y)
2 and 4
(x + 2y)(x + 4y)
Answer: (x + 2y)(x + 4y)
(x + 3y)(x − 3y)
Answer: (x + 3y)(x − 3y)
(x + 4y)²
Answer: (x + 4y)²
−3 and 2
(x − 3y)(x + 2y)
Answer: (x − 3y)(x + 2y)
GCF, or a > 1 with small numbers.
GCF = 2
2(x² + 5xy + 6y²)
2(x + 2y)(x + 3y)
Answer: 2(x + 2y)(x + 3y)
3(x² + 3xy + 2y²)
3(x + y)(x + 2y)
Answer: 3(x + y)(x + 2y)
Slide 2 onto 3y²: think x² + 7x + 6, then (x + 1)(x + 6).
Divide: (2x + 1)(x + 3y)
Check: 2x² + 6xy + xy + 3y² = 2x² + 7xy + 3y²
Answer: (2x + 1)(x + 3y)
(x − 2y)²
Answer: (x − 2y)²
(2x + 3y)(2x − 3y)
Answer: (2x + 3y)(2x − 3y)
4 and −3
(x + 4y)(x − 3y)
Answer: (x + 4y)(x − 3y)
Slide with y, or two variables and a GCF.
Slide 3: x² + 11x + 18 → (x + 2)(x + 9).
Divide 2 and 9 by 3: (3x + 2y)(x + 3y)
Check: 3x² + 9xy + 2xy + 6y² = 3x² + 11xy + 6y²
Answer: (3x + 2y)(x + 3y)
(2x + y)(x − 3y)
Answer: (2x + y)(x − 3y)
4(x² + 5xy + 6y²)
4(x + 2y)(x + 3y)
Answer: 4(x + 2y)(x + 3y)
(3x − y)(2x + 3y)
Answer: (3x − y)(2x + 3y)
(3x − 2y)²
Answer: (3x − 2y)²
(x + 4y)(x − 4y)
Answer: (x + 4y)(x − 4y)
x² + 3xy + 2xy + 6y²
The four regions are x², 3xy, 2xy, and 6y².
Answer: x² + 5xy + 6y²
(x + ay)(x + by)
Answer: (x + ay)(x + by)
(2x + 3y)(x + y) = 2x² + 2xy + 3xy + 3y² = 2x² + 5xy + 3y². Correct.
Answer: (2x + 3y)(x + y)
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