Algebra 1 · Unit 8
From a picture pattern, write a quadratic function and connect each part of the formula to the picture.
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Count, then table
Figure n = 1, 2, 3, … . Count tiles or dots. Look at first and second differences.
Constant second differences
A quadratic f(n) = an² + bn + c. The picture’s growing square or growing L often supplies the n² term.
Connect parts to the picture
n² can be an n-by-n square. A linear term can be a border. A constant can be a core that never changes.
Check the next figure
Use the formula to predict figure 4, then count if you can.
A growing square. The picture is in the question.
1, 4, 9 are 1², 2², 3².
f(n) = n²
Figure n is an n-by-n square of dots.
Answer: f(n) = n²
Squares 1, 4, 9 plus 1.
f(n) = n² + 1
The extra 1 is a dot that sits beside the square in every figure.
Answer: f(n) = n² + 1
Second differences constant (so far). Quadratic is the family to try.
Answer: quadratic
f(2) = 5, but the picture has 4 dots.
The first differences are not constant.
Answer: not linear
f(n) = n² + 1
Figure 3 has 9 + 1 = 10 tiles.
Answer: f(n) = n² + 1
f(n) = n²
Figure 2 has 4 dots.
Answer: f(n) = n²
A square plus a border, or predict figure 5.
n² + n
f(n) = n(n + 1)
The n² is the square. The +n is the extra row.
f(5) = 25 + 5 = 30
Answer: f(n) = n² + n; f(5) = 30
1+1=2, 4+2=6, 9+3=12, 16+4=20. Matches.
Each figure is a triangle of dots that makes n(n + 1) — an n by (n+1) rectangle half, but here the formula is n² + n, a square plus a side.
Answer: f(n) = n² + n
First differences 2, 2, 2. Linear: f(n) = 2n − 1.
An L can still grow by a constant amount.
Answer: f(n) = 2n − 1
n² − (n − 2)² = 4n − 4
Four sides of length n, minus 4 corners double-counted: 4(n − 1).
Answer: f(n) = 4n − 4
1+4=5, 4+4=8, 9+4=13, 16+4=20. Yes.
The +4 is a 4-tile core beside a growing square.
Answer: f(n) = n² + 4
f(n) = n² + n
n² blue, n red.
Answer: n² + n
Justify each term, or reject a wrong family.
n² + 2n + 3
Or (n + 1)² + (n + 2) = n² + 2n + 1 + n + 2 = n² + 3n + 3, which is a different picture.
Stick to the description: square n², two strips 2n, three corners +3.
f(n) = n² + 2n + 3
f(1) = 6, f(2) = 11, f(3) = 18.
Answer: f(n) = n² + 2n + 3
First: 5, 7, 9. Second: 2, 2.
1+2=3, 4+4=8, 9+6=15, 16+8=24. Yes, n² + 2n.
Answer: f(n) = n² + 2n
Each square contributes n². Two squares: 2n².
Figure 1 has 2 tiles, figure 2 has 8, figure 3 has 18.
Answer: f(n) = 2n²
Ratios 2, 2, 2. Exponential f(n) = 2ⁿ.
Second differences 2, 4, 8 are not constant.
Answer: exponential
Border 4n − 4. Diagonal of n tiles shares 2 corners with the border.
Add n − 2 interior diagonal tiles.
f(n) = 4n − 4 + n − 2 = 5n − 6.
Answer: f(n) = 5n − 6
n² − n = n(n − 1), an n by (n − 1) rectangle.
Either description is the same count.
Answer: n(n − 1)
Figure 1 has 3 tiles: a 1-by-1 square, one extra, and a core of 1.
Going to n + 1 adds 2n + 1 tiles (the usual square growth) plus 1 more for the extra side: 2n + 2.
Check: f(n+1) − f(n) = (n+1)² + (n+1) + 1 − n² − n − 1 = 2n + 1 + 1 = 2n + 2.
Answer: core 1, square, extra side
Differences 3, 5, not constant.
f(n) = n²
Answer: f(n) = n²
Each figure’s square grows with n in both directions, which is n × n.
If the picture really is that square (plus whatever the other terms name), the formula is counting the same pieces.
Answer: n² counts the square
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