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Amy Ferguson Moncure

H Algebra 2/Trig · Unit 1

Absolute Value Equations

Isolate the absolute value, split into two equations when the right side is not negative, and catch no-solution cases.

Jump to section:

|A| = k means A = k or A = −k

If k is negative, no solution.

What to Remember

Split into two equations

|A| = k means A = k or A = −k, but only when k ≥ 0.

Isolate first

If extra terms sit outside the absolute value, move them before you split.

No solution

If the isolated absolute value equals a negative number, there is no solution.

Check

Plug both candidates back in. A true absolute-value equation should match on both sides.

Level 1

Easy

Already isolated. Two solutions.

Example
Solve. |x − 4| = 6

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|x − 4| = 6

x − 4 = 6 or x − 4 = −6

First equation.

x − 4 = 6

x = 10

Second equation.

x − 4 = −6

x = −2

Answer: x = 10 or x = −2

1
Solve. |x + 2| = 5
Show Answer

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|x + 2| = 5

x + 2 = 5 or x + 2 = −5

First equation.

x + 2 = 5

x = 3

Second equation.

x + 2 = −5

x = −7

Answer: x = 3 or x = −7

2
Solve. |x − 3| = 7
Show Answer

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|x − 3| = 7

x − 3 = 7 or x − 3 = −7

First equation.

x − 3 = 7

x = 10

Second equation.

x − 3 = −7

x = −4

Answer: x = 10 or x = −4

3
Solve. |2x + 1| = 9
Show Answer

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|2x + 1| = 9

2x + 1 = 9 or 2x + 1 = −9

First equation.

2x + 1 = 9

x = 4

Second equation.

2x + 1 = −9

x = −5

Answer: x = 4 or x = −5

4
Solve. |3x − 4| = 8
Show Answer

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|3x − 4| = 8

3x − 4 = 8 or 3x − 4 = −8

First equation.

3x − 4 = 8

x = 4

Second equation.

3x − 4 = −8

x = −43

Answer: x = 4 or x = −43

5
Solve. |2x − 5| = 1
Show Answer

The formula is

|A| = k means A = k or A = −k (when k ≥ 0).

|2x − 5| = 1

2x − 5 = 1 or 2x − 5 = −1

First equation.

2x − 5 = 1

x = 3

Second equation.

2x − 5 = −1

x = 2

Answer: x = 3 or x = 2

Level 2

Medium

Isolate the absolute value, then split.

Example
Solve. |x + 2| + 5 = 11

1|x + 2| + 5 = 11

Isolate the absolute value.

1|x + 2| = 6

The formula is

|A| = k means A = k or A = −k.

x + 2 = 6 or x + 2 = −6

x = 4 or x = −8

Answer: x = 4 or x = −8

1
Solve. |x − 4| − 3 = 5
Show Answer

1|x − 4| − 3 = 5

Isolate the absolute value.

1|x − 4| = 8

The formula is

|A| = k means A = k or A = −k.

x − 4 = 8 or x − 4 = −8

x = 12 or x = −4

Answer: x = 12 or x = −4

2
Solve. 3|x − 1| = 12
Show Answer

3|x − 1| = 12

Isolate the absolute value.

|x − 1| = 4

The formula is

|A| = k means A = k or A = −k.

x − 1 = 4 or x − 1 = −4

x = 5 or x = −3

Answer: x = 5 or x = −3

3
Solve. 2|x + 3| − 4 = 10
Show Answer

2|x + 3| − 4 = 10

Isolate the absolute value.

2|x + 3| = 14

|x + 3| = 7

The formula is

|A| = k means A = k or A = −k.

x + 3 = 7 or x + 3 = −7

x = 4 or x = −10

Answer: x = 4 or x = −10

4
Solve. |4x − 1| − 6 = 9
Show Answer

1|4x − 1| − 6 = 9

Isolate the absolute value.

1|4x − 1| = 15

The formula is

|A| = k means A = k or A = −k.

4x − 1 = 15 or 4x − 1 = −15

x = 4 or x = −72

Answer: x = 4 or x = −72

5
Solve. 5|2x + 3| = 20
Show Answer

5|2x + 3| = 20

Isolate the absolute value.

|2x + 3| = 4

The formula is

|A| = k means A = k or A = −k.

2x + 3 = 4 or 2x + 3 = −4

x = 12 or x = −72

Answer: x = 12 or x = −72

Level 3

Hard

No solution, or a coefficient outside and inside.

Example
Solve. |x − 2| + 9 = 4

1|x − 2| + 9 = 4

Isolate the absolute value.

1|x − 2| = −5

Absolute value is never negative.

No solution.

Answer: no solution

1
Solve. |3x + 1| + 8 = 2
Show Answer

1|3x + 1| + 8 = 2

Isolate the absolute value.

1|3x + 1| = −6

Absolute value is never negative.

No solution.

Answer: no solution

2
Solve. 4|x − 5| − 7 = 9
Show Answer

4|x − 5| − 7 = 9

Isolate the absolute value.

4|x − 5| = 16

|x − 5| = 4

The formula is

|A| = k means A = k or A = −k.

x − 5 = 4 or x − 5 = −4

x = 9 or x = 1

Answer: x = 9 or x = 1

3
Solve. 2|3x − 1| − 8 = 6
Show Answer

2|3x − 1| − 8 = 6

Isolate the absolute value.

2|3x − 1| = 14

|3x − 1| = 7

The formula is

|A| = k means A = k or A = −k.

3x − 1 = 7 or 3x − 1 = −7

x = 83 or x = −2

Answer: x = 83 or x = −2

4
Solve. |5x + 2| − 11 = −3
Show Answer

1|5x + 2| − 11 = −3

Isolate the absolute value.

1|5x + 2| = 8

The formula is

|A| = k means A = k or A = −k.

5x + 2 = 8 or 5x + 2 = −8

x = 65 or x = −2

Answer: x = 65 or x = −2

5
Solve. 3|2x − 7| + 1 = 1
Show Answer

3|2x − 7| + 1 = 1

Isolate the absolute value.

3|2x − 7| = 0

|2x − 7| = 0

2x − 7 = 0

x = 72

Answer: x = 72

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