H Algebra 2/Trig · Unit 2
Solve ax² + bx + c = 0 with the quadratic formula. Leave answers in simplest radical form, including i.
x² + 2x − 3 = 0
x = −2 ± √(2² − 4(1)(−3))2
x = −2 ± √(4 − (−12))2
x = −2 ± √(4 + 12)2
x = −2 ± √162
x = −2 ± 42
x = −2 + 42
x = 22
x = 1
x = −2 − 42
x = −62
x = −3
x = 1 and x = −3
x = −b ± √(b² − 4ac)2a
x = −(−3) ± √((−3)² − 4(2)(−1))4
x = 3 ± √(9 − (−8))4
x = 3 ± √(9 + 8)4
x = 3 ± √174
x = 3 ± √174
x² = −4x + 1
x² + 4x − 1 = 0
x = −b ± √(b² − 4ac)2a
x = −4 ± √(4² − 4(1)(−1))2
x = −4 ± √(16 − (−4))2
x = −4 ± √(16 + 4)2
x = −4 ± √202
x = −4 ± 2√52
x = −2 ± √5
x = −2 ± √5
The equation is set equal to zero. Integer or fraction solutions.
x = −b ± √(b² − 4ac)2a
x = −4 ± √(4² − 4(1)(3))2
x = −4 ± √(16 − 12)2
x = −4 ± √42
x = −4 ± 22
x = −4 + 22
x = −22
x = −1
x = −4 − 22
x = −62
x = −3
Answer: x = −1 and x = −3
x = −b ± √(b² − 4ac)2a
x = −(−3) ± √((−3)² − 4(2)(−2))4
x = 3 ± √(9 − (−16))4
x = 3 ± √(9 + 16)4
x = 3 ± √254
x = 3 ± 54
x = 3 + 54
x = 84
x = 2
x = 3 − 54
x = −24
x = −12
Answer: x = 2 and x = −12
x = −b ± √(b² − 4ac)2a
x = −(−5) ± √((−5)² − 4(1)(−6))2
x = 5 ± √(25 − (−24))2
x = 5 ± √(25 + 24)2
x = 5 ± √492
x = 5 ± 72
x = 5 + 72
x = 122
x = 6
x = 5 − 72
x = −22
x = −1
Answer: x = 6 and x = −1
x = −b ± √(b² − 4ac)2a
x = −4 ± √(4² − 4(3)(−4))6
x = −4 ± √(16 − (−48))6
x = −4 ± √(16 + 48)6
x = −4 ± √646
x = −4 ± 86
x = −4 + 86
x = 46
x = 23
x = −4 − 86
x = −126
x = −2
Answer: x = 23 and x = −2
x = −b ± √(b² − 4ac)2a
x = −(−10) ± √((−10)² − 4(1)(25))2
x = 10 ± √(100 − 100)2
x = 10 ± √02
x = 10 ± 02
x = 102
x = 5
Answer: x = 5
The equation is set equal to zero. Two solutions with radicals.
x = −b ± √(b² − 4ac)2a
x = −4 ± √(4² − 4(1)(−1))2
x = −4 ± √(16 − (−4))2
x = −4 ± √(16 + 4)2
x = −4 ± √202
x = −4 ± 2√52
x = −2 ± √5
Answer: x = −2 ± √5
x = −b ± √(b² − 4ac)2a
x = −(−6) ± √((−6)² − 4(1)(4))2
x = 6 ± √(36 − 16)2
x = 6 ± √202
x = 6 ± 2√52
x = 3 ± √5
Answer: x = 3 ± √5
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(2)(−1))4
x = −2 ± √(4 − (−8))4
x = −2 ± √(4 + 8)4
x = −2 ± √124
x = −2 ± 2√34
x = −1 ± √32
Answer: x = −1 ± √32
x = −b ± √(b² − 4ac)2a
x = −(−4) ± √((−4)² − 4(3)(−1))6
x = 4 ± √(16 − (−12))6
x = 4 ± √(16 + 12)6
x = 4 ± √286
x = 4 ± 2√76
x = 2 ± √73
Answer: x = 2 ± √73
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(1)(−5))2
x = −2 ± √(4 − (−20))2
x = −2 ± √(4 + 20)2
x = −2 ± √242
x = −2 ± 2√62
x = −1 ± √6
Answer: x = −1 ± √6
The equation is set equal to zero. Imaginary solutions.
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(1)(5))2
x = −2 ± √(4 − 20)2
x = −2 ± √(−16)2
x = −2 ± i√162
x = −2 ± 4i2
x = −1 ± 2i
Answer: x = −1 ± 2i
x = −b ± √(b² − 4ac)2a
x = −(−6) ± √((−6)² − 4(1)(13))2
x = 6 ± √(36 − 52)2
x = 6 ± √(−16)2
x = 6 ± i√162
x = 6 ± 4i2
x = 3 ± 2i
Answer: x = 3 ± 2i
x = −b ± √(b² − 4ac)2a
x = −4 ± √(4² − 4(2)(5))4
x = −4 ± √(16 − 40)4
x = −4 ± √(−24)4
x = −4 ± i√244
x = −4 ± 2i√64
x = −2 ± i√62
Answer: x = −2 ± i√62
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(3)(2))6
x = −2 ± √(4 − 24)6
x = −2 ± √(−20)6
x = −2 ± i√206
x = −2 ± 2i√56
x = −1 ± i√53
Answer: x = −1 ± i√53
x = −b ± √(b² − 4ac)2a
x = −(−2) ± √((−2)² − 4(2)(5))4
x = 2 ± √(4 − 40)4
x = 2 ± √(−36)4
x = 2 ± i√364
x = 2 ± 6i4
x = 1 ± 3i2
Answer: x = 1 ± 3i2
The equation is not set equal to zero. One, two, or zero real solutions.
2x² + 5x = −2
2x² + 5x + 2 = 0
x = −b ± √(b² − 4ac)2a
x = −5 ± √(5² − 4(2)(2))4
x = −5 ± √(25 − 16)4
x = −5 ± √94
x = −5 ± 34
x = −5 + 34
x = −24
x = −12
x = −5 − 34
x = −84
x = −2
Answer: x = −12 and x = −2
2x² = 6x − 1
2x² − 6x + 1 = 0
x = −b ± √(b² − 4ac)2a
x = −(−6) ± √((−6)² − 4(2)(1))4
x = 6 ± √(36 − 8)4
x = 6 ± √284
x = 6 ± 2√74
x = 3 ± √72
Answer: x = 3 ± √72
x² − 4x + 7 = 3
x² − 4x + 4 = 0
x = −b ± √(b² − 4ac)2a
x = −(−4) ± √((−4)² − 4(1)(4))2
x = 4 ± √(16 − 16)2
x = 4 ± √02
x = 4 ± 02
x = 42
x = 2
Answer: x = 2
x² + 4x + 9 = 2x
x² + 2x + 9 = 0
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(1)(9))2
x = −2 ± √(4 − 36)2
x = −2 ± √(−32)2
x = −2 ± i√322
x = −2 ± 4i√22
x = −1 ± 2i√2
Answer: x = −1 ± 2i√2
2x² + 3x = 2
2x² + 3x − 2 = 0
x = −b ± √(b² − 4ac)2a
x = −3 ± √(3² − 4(2)(−2))4
x = −3 ± √(9 − (−16))4
x = −3 ± √(9 + 16)4
x = −3 ± √254
x = −3 ± 54
x = −3 + 54
x = 24
x = 12
x = −3 − 54
x = −84
x = −2
Answer: x = 12 and x = −2
A mix from every level. Use this to see if you are ready.
x = −b ± √(b² − 4ac)2a
x = −(−7) ± √((−7)² − 4(2)(3))4
x = 7 ± √(49 − 24)4
x = 7 ± √254
x = 7 ± 54
x = 7 + 54
x = 124
x = 3
x = 7 − 54
x = 24
x = 12
Answer: x = 3 and x = 12
x = −b ± √(b² − 4ac)2a
x = −2 ± √(2² − 4(1)(−4))2
x = −2 ± √(4 − (−16))2
x = −2 ± √(4 + 16)2
x = −2 ± √202
x = −2 ± 2√52
x = −1 ± √5
Answer: x = −1 ± √5
x² − 10x + 28 = 3
x² − 10x + 25 = 0
x = −b ± √(b² − 4ac)2a
x = −(−10) ± √((−10)² − 4(1)(25))2
x = 10 ± √(100 − 100)2
x = 10 ± √02
x = 10 ± 02
x = 102
x = 5
Answer: x = 5
x = −b ± √(b² − 4ac)2a
x = −(−4) ± √((−4)² − 4(1)(13))2
x = 4 ± √(16 − 52)2
x = 4 ± √(−36)2
x = 4 ± i√362
x = 4 ± 6i2
x = 2 ± 3i
Answer: x = 2 ± 3i
3x² = 4x + 4
3x² − 4x − 4 = 0
x = −b ± √(b² − 4ac)2a
x = −(−4) ± √((−4)² − 4(3)(−4))6
x = 4 ± √(16 − (−48))6
x = 4 ± √(16 + 48)6
x = 4 ± √646
x = 4 ± 86
x = 4 + 86
x = 126
x = 2
x = 4 − 86
x = −46
x = −23
Answer: x = 2 and x = −23
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