H Algebra 2/Trig · Unit 2
Turn each root into a factor and write the equation in root form. If no point is given, any a works, so choose a = 1. If a point is given, use it to find a.
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any quadratic, choose a=1 for easy math!
If x = −1
| x | = | −1 |
| + 1 | + 1 |
Add 1 to both sides.
x + 1 = 0
so (x + 1) is a factor.
If x = 5
| x | = | 5 |
| − 5 | − 5 |
Subtract 5 from both sides.
x − 5 = 0
so (x − 5) is a factor.
If the problem doesn't tell you a point the graph goes through, then a can be anything. Choose 1 to make the problem easy.
No point is given, so choose a = 1.
If x = −6
| x | = | −6 |
| + 6 | + 6 |
Add 6 to both sides.
x + 6 = 0
so (x + 6) is a factor.
If x = 3
| x | = | 3 |
| − 3 | − 3 |
Subtract 3 from both sides.
x − 3 = 0
so (x − 3) is a factor.
If the problem doesn't tell you a point the graph goes through, then a can be anything. Choose 1 to make the problem easy.
y = 1(x + 6)(x − 3)
Answer: y = 1(x + 6)(x − 3)
If x = −4
| x | = | −4 |
| + 4 | + 4 |
Add 4 to both sides.
x + 4 = 0
so (x + 4) is a factor.
If x = 2
| x | = | 2 |
| − 2 | − 2 |
Subtract 2 from both sides.
x − 2 = 0
so (x − 2) is a factor.
No point is given, so choose a = 1.
y = 1(x + 4)(x − 2)
Answer: y = 1(x + 4)(x − 2)
If x = −3
| x | = | −3 |
| + 3 | + 3 |
Add 3 to both sides.
x + 3 = 0
so (x + 3) is a factor.
If x = 8
| x | = | 8 |
| − 8 | − 8 |
Subtract 8 from both sides.
x − 8 = 0
so (x − 8) is a factor.
No point is given, so choose a = 1.
y = 1(x + 3)(x − 8)
Answer: y = 1(x + 3)(x − 8)
If x = −7
| x | = | −7 |
| + 7 | + 7 |
Add 7 to both sides.
x + 7 = 0
so (x + 7) is a factor.
If x = −2
| x | = | −2 |
| + 2 | + 2 |
Add 2 to both sides.
x + 2 = 0
so (x + 2) is a factor.
No point is given, so choose a = 1.
y = 1(x + 7)(x + 2)
Answer: y = 1(x + 7)(x + 2)
If x = 5
| x | = | 5 |
| − 5 | − 5 |
Subtract 5 from both sides.
x − 5 = 0
so (x − 5) is a factor.
If x = 6
| x | = | 6 |
| − 6 | − 6 |
Subtract 6 from both sides.
x − 6 = 0
so (x − 6) is a factor.
No point is given, so choose a = 1.
y = 1(x − 5)(x − 6)
Answer: y = 1(x − 5)(x − 6)
If x = 0
x = 0
so x is a factor.
If x = 9
| x | = | 9 |
| − 9 | − 9 |
Subtract 9 from both sides.
x − 9 = 0
so (x − 9) is a factor.
No point is given, so choose a = 1.
y = 1(x)(x − 9)
Answer: y = 1(x)(x − 9)
Clear each denominator, then choose a = 1.
If x = −4
| x | = | −4 |
| + 4 | + 4 |
Add 4 to both sides.
x + 4 = 0
so (x + 4) is a factor.
If x = 23
| x | = | 23 |
| × 3 | × 3 |
Multiply both sides by 3.
3x = 2
| 3x | = | 2 |
| − 2 | − 2 |
Subtract 2 from both sides.
3x − 2 = 0
so (3x − 2) is a factor.
If the problem doesn't tell you a point the graph goes through, then a can be anything. Choose 1 to make the problem easy.
y = 1(x + 4)(3x − 2)
Answer: y = 1(x + 4)(3x − 2)
If x = −12
| x | = | −12 |
| × 2 | × 2 |
Multiply both sides by 2.
2x = −1
| 2x | = | −1 |
| + 1 | + 1 |
Add 1 to both sides.
2x + 1 = 0
so (2x + 1) is a factor.
If x = 6
| x | = | 6 |
| − 6 | − 6 |
Subtract 6 from both sides.
x − 6 = 0
so (x − 6) is a factor.
No point is given, so choose a = 1.
y = 1(2x + 1)(x − 6)
Answer: y = 1(2x + 1)(x − 6)
If x = −2
| x | = | −2 |
| + 2 | + 2 |
Add 2 to both sides.
x + 2 = 0
so (x + 2) is a factor.
If x = 35
| x | = | 35 |
| × 5 | × 5 |
Multiply both sides by 5.
5x = 3
| 5x | = | 3 |
| − 3 | − 3 |
Subtract 3 from both sides.
5x − 3 = 0
so (5x − 3) is a factor.
No point is given, so choose a = 1.
y = 1(x + 2)(5x − 3)
Answer: y = 1(x + 2)(5x − 3)
If x = −43
| x | = | −43 |
| × 3 | × 3 |
Multiply both sides by 3.
3x = −4
| 3x | = | −4 |
| + 4 | + 4 |
Add 4 to both sides.
3x + 4 = 0
so (3x + 4) is a factor.
If x = 1
| x | = | 1 |
| − 1 | − 1 |
Subtract 1 from both sides.
x − 1 = 0
so (x − 1) is a factor.
No point is given, so choose a = 1.
y = 1(3x + 4)(x − 1)
Answer: y = 1(3x + 4)(x − 1)
If x = 25
| x | = | 25 |
| × 5 | × 5 |
Multiply both sides by 5.
5x = 2
| 5x | = | 2 |
| − 2 | − 2 |
Subtract 2 from both sides.
5x − 2 = 0
so (5x − 2) is a factor.
If x = 12
| x | = | 12 |
| × 2 | × 2 |
Multiply both sides by 2.
2x = 1
| 2x | = | 1 |
| − 1 | − 1 |
Subtract 1 from both sides.
2x − 1 = 0
so (2x − 1) is a factor.
No point is given, so choose a = 1.
y = 1(5x − 2)(2x − 1)
Answer: y = 1(5x − 2)(2x − 1)
If x = −34
| x | = | −34 |
| × 4 | × 4 |
Multiply both sides by 4.
4x = −3
| 4x | = | −3 |
| + 3 | + 3 |
Add 3 to both sides.
4x + 3 = 0
so (4x + 3) is a factor.
If x = 13
| x | = | 13 |
| × 3 | × 3 |
Multiply both sides by 3.
3x = 1
| 3x | = | 1 |
| − 1 | − 1 |
Subtract 1 from both sides.
3x − 1 = 0
so (3x − 1) is a factor.
No point is given, so choose a = 1.
y = 1(4x + 3)(3x − 1)
Answer: y = 1(4x + 3)(3x − 1)
One root is listed. Use that factor twice.
Only one root is listed, so it is a double root.
If x = 4
| x | = | 4 |
| − 4 | − 4 |
Subtract 4 from both sides.
x − 4 = 0
so (x − 4) is a factor.
Use the factor twice.
If the problem doesn't tell you a point the graph goes through, then a can be anything. Choose 1 to make the problem easy.
y = 1(x − 4)²
Answer: y = 1(x − 4)²
Only one root is listed, so it is a double root.
If x = −3
| x | = | −3 |
| + 3 | + 3 |
Add 3 to both sides.
x + 3 = 0
so (x + 3) is a factor.
Use the factor twice.
No point is given, so choose a = 1.
y = 1(x + 3)²
Answer: y = 1(x + 3)²
Only one root is listed, so it is a double root.
If x = 7
| x | = | 7 |
| − 7 | − 7 |
Subtract 7 from both sides.
x − 7 = 0
so (x − 7) is a factor.
Use the factor twice.
No point is given, so choose a = 1.
y = 1(x − 7)²
Answer: y = 1(x − 7)²
Only one root is listed, so it is a double root.
If x = −5
| x | = | −5 |
| + 5 | + 5 |
Add 5 to both sides.
x + 5 = 0
so (x + 5) is a factor.
Use the factor twice.
No point is given, so choose a = 1.
y = 1(x + 5)²
Answer: y = 1(x + 5)²
Only one root is listed, so it is a double root.
If x = 23
| x | = | 23 |
| × 3 | × 3 |
Multiply both sides by 3.
3x = 2
| 3x | = | 2 |
| − 2 | − 2 |
Subtract 2 from both sides.
3x − 2 = 0
so (3x − 2) is a factor.
Use the factor twice.
No point is given, so choose a = 1.
y = 1(3x − 2)²
Answer: y = 1(3x − 2)²
Only one root is listed, so it is a double root.
If x = −34
| x | = | −34 |
| × 4 | × 4 |
Multiply both sides by 4.
4x = −3
| 4x | = | −3 |
| + 3 | + 3 |
Add 3 to both sides.
4x + 3 = 0
so (4x + 3) is a factor.
Use the factor twice.
No point is given, so choose a = 1.
y = 1(4x + 3)²
Answer: y = 1(4x + 3)²
x = −2, so (x + 2) is a factor.
x = 4, so (x − 4) is a factor.
y = a(x − r)(x − s)
y = a(x + 2)(x − 4)
Substitute (0, −4).
−4 = a(0 + 2)(0 − 4)
−4 = a(2)(−4)
−4 = −8a
Divide both sides by −8.
a = −4−8
a = 12
The roots and a point are given. The point tells you a. Answer in root form.
x = −5, so (x + 5) is a factor.
x = 1, so (x − 1) is a factor.
y = a(x − r)(x − s)
y = a(x + 5)(x − 1)
Substitute (0, −10).
−10 = a(0 + 5)(0 − 1)
−10 = a(5)(−1)
−10 = −5a
Divide both sides by −5.
a = −10−5
a = 2
y = 2(x + 5)(x − 1)
Answer: y = 2(x + 5)(x − 1)
x = 3, so (x − 3) is a factor.
x = 6, so (x − 6) is a factor.
y = a(x − r)(x − s)
y = a(x − 3)(x − 6)
Substitute (4, 2).
2 = a(4 − 3)(4 − 6)
2 = a(1)(−2)
2 = −2a
Divide both sides by −2.
a = 2−2
a = −1
y = −1(x − 3)(x − 6)
Answer: y = −1(x − 3)(x − 6)
x = −3, so (x + 3) is a factor.
x = 3, so (x − 3) is a factor.
y = a(x − r)(x − s)
y = a(x + 3)(x − 3)
Substitute (1, −4).
−4 = a(1 + 3)(1 − 3)
−4 = a(4)(−2)
−4 = −8a
Divide both sides by −8.
a = −4−8
a = 12
y = 12(x + 3)(x − 3)
Answer: y = 12(x + 3)(x − 3)
x = −6, so (x + 6) is a factor.
x = 0, so x is a factor.
y = a(x − r)(x − s)
y = a(x + 6)(x)
Substitute (−2, −12).
−12 = a(−2 + 6)(−2)
−12 = a(4)(−2)
−12 = −8a
Divide both sides by −8.
a = −12−8
a = 32
y = 32(x + 6)(x)
Answer: y = 32(x + 6)(x)
x = −1, so (x + 1) is a factor.
x = 1, so (x − 1) is a factor.
y = a(x − r)(x − s)
y = a(x + 1)(x − 1)
Substitute (3, 6).
6 = a(3 + 1)(3 − 1)
6 = a(4)(2)
6 = 8a
Divide both sides by 8.
a = 68
a = 34
y = 34(x + 1)(x − 1)
Answer: y = 34(x + 1)(x − 1)
Read the roots from the x-intercepts. Use the labeled point, or choose a marked point that is not a root. Answer in root form.
The x-intercepts are the roots.
x = −2, so (x + 2) is a factor.
x = 2, so (x − 2) is a factor.
The labeled point is (0, −4).
y = a(x − r)(x − s)
y = a(x + 2)(x − 2)
Substitute (0, −4).
−4 = a(0 + 2)(0 − 2)
−4 = a(2)(−2)
−4 = −4a
Divide both sides by −4.
a = −4−4
a = 1
y = 1(x + 2)(x − 2)
Answer: y = 1(x + 2)(x − 2)
The x-intercepts are the roots.
x = 0, so x is a factor.
x = 4, so (x − 4) is a factor.
The labeled point is (2, 4).
y = a(x − r)(x − s)
y = a(x)(x − 4)
Substitute (2, 4).
4 = a(2)(2 − 4)
4 = a(2)(−2)
4 = −4a
Divide both sides by −4.
a = 4−4
a = −1
y = −1(x)(x − 4)
Answer: y = −1(x)(x − 4)
The x-intercepts are the roots.
x = −1, so (x + 1) is a factor.
x = 3, so (x − 3) is a factor.
Use (1, −4).
(0, −3) gives the same a.
y = a(x − r)(x − s)
y = a(x + 1)(x − 3)
Substitute (1, −4).
−4 = a(1 + 1)(1 − 3)
−4 = a(2)(−2)
−4 = −4a
Divide both sides by −4.
a = −4−4
a = 1
y = 1(x + 1)(x − 3)
Answer: y = 1(x + 1)(x − 3)
The x-intercepts are the roots.
x = −4, so (x + 4) is a factor.
x = 0, so x is a factor.
Use (−2, −4).
(−3, −3) gives the same a.
y = a(x − r)(x − s)
y = a(x + 4)(x)
Substitute (−2, −4).
−4 = a(−2 + 4)(−2)
−4 = a(2)(−2)
−4 = −4a
Divide both sides by −4.
a = −4−4
a = 1
y = 1(x + 4)(x)
Answer: y = 1(x + 4)(x)
The x-intercepts are the roots.
x = 2, so (x − 2) is a factor.
x = 6, so (x − 6) is a factor.
Use (4, −2).
(0, 6) gives the same a.
y = a(x − r)(x − s)
y = a(x − 2)(x − 6)
Substitute (4, −2).
−2 = a(4 − 2)(4 − 6)
−2 = a(2)(−2)
−2 = −4a
Divide both sides by −4.
a = −2−4
a = 12
y = 12(x − 2)(x − 6)
Answer: y = 12(x − 2)(x − 6)
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