H Algebra 2/Trig · Unit 4
Find the constant of direct variation, then find the new value.
The formula
Direct variation means y = kx.
k is the constant of variation.
Find k first
Rearrange to k = yx.
Substitute the given pair, then reduce.
A square
If y varies directly with the square of x, the formula is y = kx².
Then k = yx².
Use the new x
Write y = kx with the value of k you found.
Substitute the new x and simplify.
y = kx
y = kx
k = yx
k = 204
k = 5
y = 5x
y = 5×7
y = 35
Answer: y = 35
y = kx
k = yx
k = 186
k = 3
y = 3x
y = 3×10
y = 30
Answer: y = 30
y = kx
k = yx
k = 123
k = 4
y = 4x
y = 4×8
y = 32
Answer: y = 32
y = kx
k = yx
k = 287
k = 4
y = 4x
y = 4×5
y = 20
Answer: y = 20
y = kx
k = yx
k = 459
k = 5
y = 5x
y = 5×4
y = 20
Answer: y = 20
y = kx
k = yx
k = 162
k = 8
y = 8x
y = 8×9
y = 72
Answer: y = 72
y varies directly with the square of x
y = kx²
k = yx²
x² = 4
k = 124
k = 3
y = 3x²
x² = 25
y = 3×25
y = 75
Answer: y = 75
y = kx²
k = yx²
x² = 9
k = 189
k = 2
y = 2x²
x² = 4
y = 2×4
y = 8
Answer: y = 8
y = kx²
k = yx²
x² = 16
k = 3216
k = 2
y = 2x²
x² = 9
y = 2×9
y = 18
Answer: y = 18
y = kx²
k = yx²
x² = 4
k = 204
k = 5
y = 5x²
x² = 36
y = 5×36
y = 180
Answer: y = 180
y = kx²
k = yx²
x² = 16
k = 4816
k = 3
y = 3x²
x² = 1
y = 3×1
y = 3
Answer: y = 3
y = kx²
k = yx²
x² = 25
k = 5025
k = 2
y = 2x²
x² = 4
y = 2×4
y = 8
Answer: y = 8
A direct-variation situation
d = kt
k = dt
k = 1503
k = 50
d = 50t
d = 50×5
d = 250
The distance is 250 miles.
Answer: The distance is 250 miles.
c = kn
k = cn
k = 124
k = 3
c = 3n
c = 3×7
c = 21
The cost is 21 dollars.
Answer: The cost is 21 dollars.
w = kn
k = wn
k = 186
k = 3
w = 3n
w = 3×10
w = 30
The weight is 30 ounces.
Answer: The weight is 30 ounces.
p = kh
k = ph
k = 486
k = 8
p = 8h
p = 8×9
p = 72
The pay is 72 dollars.
Answer: The pay is 72 dollars.
g = km
k = gm
k = 248
k = 3
g = 3m
g = 3×5
g = 15
The amount is 15 gallons.
Answer: The amount is 15 gallons.
c = km
k = cm
k = 16020
k = 8
c = 8m
c = 8×15
c = 120
The amount is 120 calories.
Answer: The amount is 120 calories.
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