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Amy Ferguson Moncure

H Algebra 2/Trig · Unit 7

Condense Logarithmic Expressions

Rewrite each expression as one logarithm. Simplify any log of a plain number before you stop.

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log M + log N = log(MN)

log M − log N = log(of a quotient)

c log M = log of M to the c

What to Remember

One log at the end

Add logs: multiply the arguments. Subtract logs: divide the arguments.

A coefficient becomes an exponent.

Roots

A coefficient of 12 is a square root. A coefficient of 13 is a cube root.

Use square root of x for a square root.

Constants can simplify

If a log of a number is itself a whole number, multiply or divide that number before you stop.

12 log3 9 = log3 3 = 1.

Level 1

Easy

Two or three logs

Example
Condense 2 log3 x + log3 y − log3 5.

Coefficient rule: c logb M = logb(M to the c).

2 log3 x = log3 x²

Product rule: add logs with the same base by multiplying the arguments.

log3 x² + log3 y = log3 x²y

Quotient rule: subtract logs with the same base by dividing the arguments.

log3 x²y − log3 5 = log3 (x²y5)

Answer: log3 (x²y5)

1
Condense log2 a + log2 b.
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Product rule: add logs with the same base by multiplying the arguments.

log2 a + log2 b

log2 ab

Answer: log2 ab

2
Condense log5 m − log5 n.
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Quotient rule: subtract logs with the same base by dividing the arguments.

log5 m − log5 n

log5 (mn)

Answer: log5 (mn)

3
Condense 3 log7 p.
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Coefficient rule: c logb M = logb(M to the c).

3 log7 p

log7 p³

Answer: log7 p³

4
Condense log x + log y − log z.
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log with no base means log10.

Product rule, then quotient rule.

log xy − log z

log xyz

Answer: log xyz

5
Condense 2 ln t + ln 4.
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Coefficient rule.

2 ln t = ln(t²)

Product rule.

ln(t²) + ln 4 = ln(4t²)

Answer: ln(4t²)

Level 2

Medium

A fraction coefficient or a root

Example
Condense 2 log5 x + 12 log5 y − log5 3.

Coefficient rule.

2 log5 x = log5 x²

12 log5 y = log5 (square root of y)

Multiply, then divide.

log5 (x²square root of y3)

Answer: log5 (x²square root of y3)

1
Condense 3 log2 a − 2 log2 b + log2 c.
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3 log2 a = log2 a³

2 log2 b = log2 b²

log2 (a³cb²)

Answer: log2 (a³cb²)

2
Condense ln 5 + 13 ln x − 2 ln y.
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13 ln x = ln(\(x^{\frac{1}{3}}\))

2 ln y = ln(y²)

ln 5\(x^{\frac{1}{3}}\)y²

Answer: ln 5 \(x^{\frac{1}{3}}\)y²

3
Condense 4 log3 x + 12 log3 9 − log3 y.
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12 log3 9 = log3 (square root of 9)

square root of 9 = 3

12 log3 9 = log3 3

4 log3 x = log3 x⁴

log3 (3x⁴y)

Answer: log3 (3x⁴y)

4
Condense log7 4 + log7 x − 2 log7 y.
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2 log7 y = log7 y²

log7 (4xy²)

Answer: log7 (4xy²)

5
Condense 2 log2 8 + log2 x − log2 4.
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2 log2 8 = log2 8²

8² = 64

log2 64 − log2 4 = log2 (644)

644 = 16

log2 16x

Answer: log2 16x

Level 3

Hard

Four logs, and constants that simplify

Example
Condense ln 9 − 2 ln p + 12 ln q − ln 3.

2 ln p = ln(p²)

12 ln q = ln(square root of q)

ln 9square root of q3p²

93 = 3

ln 3square root of qp²

Answer: ln 3square root of qp²

1
Condense 2 log5 x + log5 10 − 3 log5 y − log5 2.
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2 log5 x = log5 x²

3 log5 y = log5 y³

log5 (10x²2y³)

102 = 5

log5 (5x²y³)

Answer: log5 (5x²y³)

2
Condense 3 log4 a + 12 log4 b − log4 c − 2 log4 a.
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3 log4 a − 2 log4 a = log4 a

12 log4 b = log4 (square root of b)

log4 (asquare root of bc)

Answer: log4 (asquare root of bc)

3
Condense ln 8 + 13 ln x − ln 2 − 2 ln y.
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ln 8 − ln 2 = ln 82

82 = 4

13 ln x = ln(\(x^{\frac{1}{3}}\))

2 ln y = ln(y²)

ln 4\(x^{\frac{1}{3}}\)y²

Answer: ln 4 \(x^{\frac{1}{3}}\)y²

4
Condense log6 18 − log6 3 + 2 log6 x − 12 log6 y.
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log6 18 − log6 3 = log6 (183)

183 = 6

2 log6 x = log6 x²

12 log6 y = log6 (square root of y)

log6 (6x²square root of y)

Answer: log6 (6x²square root of y)

5
Condense 4 log3 m + 12 log3 9 − log3 n − log3 3.
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12 log3 9 = log3 3

log3 3 − log3 3 = 0

4 log3 m = log3 m⁴

log3 (m⁴n)

Answer: log3 (m⁴n)

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