H Algebra 2/Trig · Unit 7
Rewrite one logarithm as a sum or difference. A root becomes a fraction coefficient. A plain number log that you know exactly should be written as that number.
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One log becomes a sum or a difference
A product inside the log becomes a sum. A quotient becomes a difference.
An exponent inside becomes a coefficient.
Roots become coefficients
is x to the power 12, so it contributes a coefficient of 12.
A cube root of x2 contributes a coefficient of 23.
A plain number may simplify
log5 25 = 2. When you expand, write that 2, not log5 25.
Products, quotients, and whole-number powers
Quotient rule: a quotient becomes a difference.
log2 x³y − log2 5
Product rule, then the power rule.
3 log2 x + log2 y − log2 5
Answer: 3 log2 x + log2 y − log2 5
Product rule.
log3 a + log3 b
Answer: log3 a + log3 b
Quotient rule.
log5 m − log5 n
Answer: log5 m − log5 n
Power rule: an exponent becomes a coefficient.
4 log7 p
Answer: 4 log7 p
Product rule.
ln 4 + ln(t²)
Power rule.
ln 4 + 2 ln t
Answer: ln 4 + 2 ln t
log with no base means log10.
log x + log y − log z
Answer: log x + log y − log z
A square root or a cube root
Quotient rule.
log 6a² − log c
Product rule and power rule.
log 6 + 2 log a + 12 log b − log c
Answer: log 6 + 2 log a + 12 log b − log c
Quotient rule, then power rule.
3 log4 x − 12 log4 y
Answer: 3 log4 x − 12 log4 y
12 log2 a − 3 log2 b
Answer: 12 log2 a − 3 log2 b
Product rule.
2 ln p + ln(\(\sqrt[3]{q}\))
A cube root is a power of 13.
2 ln p + 13 ln q
Answer: 2 ln p + 13 ln q
log5 25 + 4 log5 x − log5 y
log5 25 = 2
2 + 4 log5 x − log5 y
Answer: 2 + 4 log5 x − log5 y
2 log3 a + log3 b − 5 log3 c
Answer: 2 log3 a + log3 b − 5 log3 c
A rational power and a constant that simplifies
Quotient rule.
log2 7\(\sqrt[3]{m^{2}}\) − log2 n⁴p
The cube root of m² is m to the power 23.
log2 7 + 23 log2 m − 4 log2 n − log2 p
Answer: log2 7 + 23 log2 m − 4 log2 n − log2 p
log5 3 + 23 log5 x − log5 y − 4 log5 z
Answer: log5 3 + 23 log5 x − log5 y − 4 log5 z
12 log4 x + 3 log4 y − log4 8 − 2 log4 w
8 = 2³ and 4 = 2², so log4 8 = 32.
12 log4 x + 3 log4 y − 32 − 2 log4 w
Answer: 12 log4 x + 3 log4 y − 32 − 2 log4 w
ln(e²) + ln() − ln(y³)
ln(e²) = 2
2 + 12 ln x − 3 ln y
Answer: 2 + 12 ln x − 3 ln y
5 log6 a − 12 log6 b − 2 log6 c
Answer: 5 log6 a − 12 log6 b − 2 log6 c
log3 9 + 23 log3 x − log3 y − 4 log3 w
log3 9 = 2
2 + 23 log3 x − log3 y − 4 log3 w
Answer: 2 + 23 log3 x − log3 y − 4 log3 w
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