H Algebra 2/Trig · Unit 8
Find how many standard deviations a value is from the mean, or use normalcdf for a probability.
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Standard deviations from the mean
Subtract the mean from the value, then divide by the standard deviation.
A negative result is below the mean.
normalcdf
normalcdf(lower, upper, mean, standard deviation) gives the probability between the two bounds.
Use a large negative lower bound for “below,” and a large upper bound for “above.”
How many standard deviations?
z = value − meanstandard deviation
z = 75 − 8010
z = −510
z = −12
12 standard deviations below the mean
Answer: 12 standard deviations below the mean
z = value − meanstandard deviation
z = 80 − 648
z = 168
z = 2
2 standard deviations above the mean
Answer: 2 standard deviations above the mean
z = value − meanstandard deviation
z = 44 − 5012
z = −612
z = −12
12 standard deviations below the mean
Answer: 12 standard deviations below the mean
z = value − meanstandard deviation
z = 104 − 9616
z = 816
z = 12
12 standard deviations above the mean
Answer: 12 standard deviations above the mean
z = value − meanstandard deviation
z = 61 − 706
z = −96
z = −32
32 standard deviations below the mean
Answer: 32 standard deviations below the mean
z = value − meanstandard deviation
z = 90 − 904
z = 04
z = 0
0. The value is the mean.
Answer: 0. The value is the mean.
A probability to the nearest thousandth
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(15, 24, 18, 4)
Round the probability to the nearest thousandth.
0.707
Answer: 0.707
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(−99999, 80, 74, 8)
Round the probability to the nearest thousandth.
0.773
Answer: 0.773
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(72, 99999, 66, 3)
Round the probability to the nearest thousandth.
0.023
Answer: 0.023
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(34, 52, 40, 6)
Round the probability to the nearest thousandth.
0.819
Answer: 0.819
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(−99999, 22, 28, 5)
Round the probability to the nearest thousandth.
0.115
Answer: 0.115
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(64, 99999, 55, 7)
Round the probability to the nearest thousandth.
0.099
Answer: 0.099
How many people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(−99999, 75, 70, 5)
Multiply that probability by the number of people.
0.841 × 200 = 168.200
Round to the nearest whole number.
168
Answer: 168 people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(70, 90, 82, 9)
Multiply that probability by the number of people.
0.722 × 150 = 108.300
Round to the nearest whole number.
108
Answer: 108 people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(41, 99999, 36, 4)
Multiply that probability by the number of people.
0.106 × 120 = 12.720
Round to the nearest whole number.
13
Answer: 13 people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(−99999, 42, 48, 6)
Multiply that probability by the number of people.
0.159 × 80 = 12.720
Round to the nearest whole number.
13
Answer: 13 people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(78, 102, 90, 12)
Multiply that probability by the number of people.
0.683 × 180 = 122.940
Round to the nearest whole number.
123
Answer: 123 people
Use normalcdf(lower, upper, mean, standard deviation).
normalcdf(30, 99999, 24, 5)
Multiply that probability by the number of people.
0.115 × 175 = 20.125
Round to the nearest whole number.
20
Answer: 20 people
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