Calculus BC ยท Unit 1
Use both sides of a table. A function value, an average of the two sides, or one huge output is not automatically the limit.
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A table is evidence, not a proof
If the y-values get close to one number from both sides, that number is the best estimate of the limit. A single output in the table is not the limit.
Check the two sides separately
If the left-hand values and the right-hand values approach different numbers, the two-sided limit does not exist. Do not average those two numbers.
The function value is a separate box
If the table lists \(f(a)\), compare it with the limit. Continuity needs those to be equal. If \(f(a)\) is missing, the table cannot show continuity.
Unbounded growth
If the outputs grow without a ceiling as x approaches a from one side, estimate that one-sided limit as \(\infty\) or \(-\infty\).
Say what the numbers are approaching.
| \(x\) | 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 7.2 | 7.02 | 7.002 | 6.998 | 6.98 | 6.8 |
From the left, the values 7.2, 7.02, 7.002 approach 7.
From the right, the values 6.998, 6.98, 6.8 approach 7.
Both sides approach the same number.
\(\lim_{x \to 2} f(x) = 7\)
\(f(2) = 0\) is not the limit.
Answer: \(7\)
| \(x\) | 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 7.2 | 7.02 | 7.002 | 6.998 | 6.98 | 6.8 |
The prompt gives the function value.
\(f(2) = 0\)
Answer: \(0\)
| \(x\) | 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 5.1 | 5.01 | 5.001 | 1.002 | 1.02 | 1.2 |
Use only the x-values less than 3: 5.1, 5.01, 5.001.
Those values approach 5.
\(\lim_{x \to 3^-} f(x) = 5\)
Answer: \(5\)
| \(x\) | 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 5.1 | 5.01 | 5.001 | 1.002 | 1.02 | 1.2 |
Use only the x-values greater than 3: 1.002, 1.02, 1.2.
Those values approach 1.
\(\lim_{x \to 3^+} f(x) = 1\)
Answer: \(1\)
| \(x\) | 1.1 | 1.01 | 1.001 |
|---|---|---|---|
| \(f(x)\) | 12 | 102 | 1002 |
The outputs 12, 102, 1002 grow without a ceiling.
\(\lim_{x \to 1^+} f(x) = \infty\)
Answer: \(\infty\)
| \(x\) | 0.9 | 0.99 | 0.999 |
|---|---|---|---|
| \(f(x)\) | \(-8\) | \(-98\) | \(-998\) |
The outputs \(-8\), \(-98\), \(-998\) grow downward without a floor.
\(\lim_{x \to 1^-} f(x) = -\infty\)
Answer: \(-\infty\)
Decide whether the two-sided limit exists, and whether the table fits continuity.
| \(x\) | 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 7.2 | 7.02 | 7.002 | 6.998 | 6.98 | 6.8 |
Both sides approach 7, so the best estimate of the limit is 7.
\(f(2) = 0 \neq 7\)
f is not continuous at 2.
Answer: B. the limit is 7
| \(x\) | 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 5.1 | 5.01 | 5.001 | 1.002 | 1.02 | 1.2 |
\(\lim_{x \to 3^-} f(x) = 5\)
\(\lim_{x \to 3^+} f(x) = 1\)
The one-sided limits are not equal.
The two-sided limit does not exist.
Answer: C. the two-sided limit does not exist
| \(x\) | 4.9 | 4.99 | 5.01 | 5.1 |
|---|---|---|---|---|
| \(g(x)\) | 2.1 | 2.01 | 1.99 | 1.9 |
Left-hand values 2.1 and 2.01 approach 2.
Right-hand values 1.99 and 1.9 approach 2.
\(\lim_{x \to 5} g(x) = 2\)
Answer: \(2\)
| \(x\) | 1.9 | 1.99 | 2 | 2.01 | 2.1 |
|---|---|---|---|---|---|
| \(f(x)\) | 4.2 | 4.02 | 9 | 3.98 | 3.8 |
Nearby values 4.2, 4.02, 3.98, 3.8 approach 4.
\(\lim_{x \to 2} f(x) = 4\)
The table lists \(f(2) = 9\).
\(4 \neq 9\), so f is not continuous at 2.
Answer: B. the limit is 4, and f is not continuous at 2
| \(x\) | \(-0.1\) | \(-0.01\) | \(-0.001\) | 0.001 | 0.01 | 0.1 |
|---|---|---|---|---|---|---|
| \(h(x)\) | 0.01 | 0.0001 | 0.000001 | 0.000001 | 0.0001 | 0.01 |
From both sides, the outputs get close to 0.
\(\lim_{x \to 0} h(x) = 0\)
Answer: \(0\)
| \(x\) | \(-0.1\) | \(-0.01\) | \(-0.001\) | 0.001 | 0.01 | 0.1 |
|---|---|---|---|---|---|---|
| \(h(x)\) | 0.01 | 0.0001 | 0.000001 | 0.000001 | 0.0001 | 0.01 |
The table supports \(\lim_{x \to 0} h(x) = 0\).
Continuity also needs \(h(0)\) to equal that limit.
\(h(0)\) is not given.
The table does not show continuity.
Answer: no
Two functions, or a conclusion a table cannot support.
| \(x\) | 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 5.1 | 5.01 | 5.001 | 1.002 | 1.02 | 1.2 |
\(\lim_{x \to 3^-} f(x) = 5\)
\(\lim_{x \to 3^+} f(x) = 1\)
The one-sided limits are not equal.
Averaging a left-hand value and a right-hand value does not produce the two-sided limit.
The two-sided limit does not exist.
Answer: does not exist
| \(x\) | 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 |
|---|---|---|---|---|---|---|
| \(f(x)\) | 7.2 | 7.02 | 7.002 | 6.998 | 6.98 | 6.8 |
\(f(2) = 0\).
\(\lim_{x \to 2} f(x) = 7\)
\(\lim_{x \to 2} \bigl(f(x)\bigr)^2 = 7^2\)
\(49\)
\(\bigl(f(2)\bigr)^2 = 0\) is not the limit.
Answer: \(49\)
| \(x\) | 1.9 | 1.99 | 2.01 | 2.1 |
|---|---|---|---|---|
| \(f(x)\) | 6.3 | 6.03 | 5.97 | 5.7 |
| \(g(x)\) | 2.4 | 2.04 | 7.96 | 7.6 |
f approaches 6 from both sides.
\(\lim_{x \to 2} f(x) = 6\)
g approaches 2 from the left and 8 from the right.
\(\lim_{x \to 2^-} g(x) = 2\)
\(\lim_{x \to 2^+} g(x) = 8\)
Left-hand limit of the sum:
\(6 + 2 = 8\)
Right-hand limit of the sum:
\(6 + 8 = 14\)
The one-sided limits differ, so the two-sided limit does not exist.
Answer: does not exist
| \(x\) | 1.9 | 1.99 | 2.01 | 2.1 |
|---|---|---|---|---|
| \(f(x)\) | 6.3 | 6.03 | 5.97 | 5.7 |
| \(g(x)\) | 2.4 | 2.04 | 7.96 | 7.6 |
f approaches 6 from both sides, so the limit of f exists.
g approaches 2 from the left and 8 from the right.
The limit of g does not exist.
5 would be an average of the two sides. That is not a limit.
The sum does not approach 11.
Answer: C. the limit of g does not exist
| \(x\) | 1.1 | 1.01 | 1.001 |
|---|---|---|---|
| \(f(x)\) | 12 | 102 | 1002 |
Each closer x-value produces a much larger output.
The outputs are not settling near one finite number.
\(\lim_{x \to 1^+} f(x) = \infty\)
Answer: C. the right-hand limit is \(\infty\)
A two-sided limit is one requirement for continuity.
Continuity at 6 also needs \(p(6)\) to be defined.
And it needs \(p(6) = \lim_{x \to 6} p(x)\).
The table does not give \(p(6)\), so continuity is not settled.
Answer: p(6) must equal the limit
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