IB · Unit 1 · 1C Logarithms
Combine like log terms, or cancel matching powers of log x or ln x in a fraction. Split a sum before you cancel.
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\(\log 10^k = k\)
\(10^{\log a} = a\)
\(\ln e^k = k\)
\(e^{\ln a} = a\)
Like terms
Treat \(\log x\) the way you treat a variable.
\(\log x + 3\log x = 4\log x\)
Cancel one power
The formula is \(\dfrac{( \log a )^n}{\log a} = (\log a)^{n-1}\) when \(\log a \neq 0\).
\(\dfrac{3(\log 5x)^2}{\log 5x} = 3\log 5x\)
Split a sum over a log
\(\dfrac{\ln x + (\ln x)^2}{\ln x} = 1 + \ln x\)
Divide each term by the denominator.
Then subtract
After you split, combine like terms.
\(1 + \ln x - \ln x = 1\)
When a question writes log with no base, that means log10.
ln means loge, the natural logarithm.
A different base is written as a subscript, for example log2 8. This is read as log base 2 of 8.
Combine like log terms.
Like terms: add the coefficients.
\(1\log x + 3\log x = 4\log x\)
Answer: \(4\log x\)
\(7\log x\)
Answer: \(7\log x\)
\(5\ln x\)
Answer: \(5\ln x\)
\(5\log x\)
Answer: \(5\log x\)
\(5\ln x\)
Answer: \(5\ln x\)
\(5\log x\)
Answer: \(5\log x\)
Cancel one matching factor of log or ln from numerator and denominator.
\(\dfrac{(\log 5x)^2}{\log 5x} = \log 5x\)
\(3\log 5x\)
Answer: \(3\log 5x\)
\(4\ln x\)
Answer: \(4\ln x\)
\(\dfrac{1}{\log 7x}\)
Answer: \(\dfrac{1}{\log 7x}\)
\(5\log 2x\)
Answer: \(5\log 2x\)
\(\ln 4x\)
Answer: \(\ln 4x\)
\(3\)
Answer: \(3\)
Split every term, cancel powers, then combine. Extra practice on rational expressions in ln x or log x.
\(\dfrac{2\ln x}{\ln x} + \dfrac{(\ln x)^2}{\ln x} - \ln x\)
\(2 + \ln x - \ln x\)
\(2\)
Answer: \(2\)
\(3 + \log x - \log x\)
\(3\)
Answer: \(3\)
\(\dfrac{\ln x}{(\ln x)^2} - \dfrac{(\ln x)^3}{(\ln x)^2}\)
\(\dfrac{1}{\ln x} - \ln x\)
Answer: \(\dfrac{1}{\ln x} - \ln x\)
\(\log x + 5\)
Answer: \(\log x + 5\)
\(4\ln x - 2\)
Answer: \(4\ln x - 2\)
\(\ln x + 2 - \ln x\)
\(2\)
Answer: \(2\)
\(6 - 2\log x\)
Answer: \(6 - 2\log x\)
\(\ln x - 4 + 4\)
\(\ln x\)
Answer: \(\ln x\)
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