IB AA ยท 12A Laws of Exponents
Change every root into a rational exponent. Add when you multiply. Subtract when you divide.
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A root is a power
The formula is
\(\sqrt[n]{a}=a^{\frac{1}{n}}\)
\(\sqrt{x}=x^{\frac{1}{2}}\)
\(\sqrt[3]{x}=x^{\frac{1}{3}}\)
Product rule
Same base, multiply: add the exponents.
\(a^m \cdot a^n = a^{m+n}\)
\(x^3\sqrt{x}=x^3\cdot x^{\frac{1}{2}}\)
\(x^{\frac{7}{2}}\)
Quotient rule
Same base, divide: subtract the exponents.
\(\dfrac{a^m}{a^n}=a^{m-n}\)
\(\dfrac{6x}{\sqrt[3]{x}}=6x^{1-\frac{1}{3}}\)
\(6x^{\frac{2}{3}}\)
Two terms
Split a sum or difference over a monomial, then write each piece as a power.
\(\dfrac{A+B}{C}=\dfrac{A}{C}+\dfrac{B}{C}\)
Write each root as a power, then add the exponents.
The formula is.\(\sqrt{x}=x^{\frac{1}{2}}\)
\(x^3\sqrt{x}=x^3\cdot x^{\frac{1}{2}}\)
The formula is.\(a^m\cdot a^n=a^{m+n}\)
\(x^{3+\frac{1}{2}}\)
\(3=\dfrac{6}{2}\)
\(\dfrac{6}{2}+\dfrac{1}{2}=\dfrac{7}{2}\)
\(x^{\frac{7}{2}}\)
Answer: \(x^{\frac{7}{2}}\)
\(x\sqrt{x}=x^1\cdot x^{\frac{1}{2}}\)
\(x^{1+\frac{1}{2}}\)
\(1=\dfrac{2}{2}\)
\(\dfrac{2}{2}+\dfrac{1}{2}=\dfrac{3}{2}\)
\(x^{\frac{3}{2}}\)
Answer: \(x^{\frac{3}{2}}\)
\(\sqrt[3]{x}=x^{\frac{1}{3}}\)
\(x^4\cdot x^{\frac{1}{3}}=x^{4+\frac{1}{3}}\)
\(4=\dfrac{12}{3}\)
\(\dfrac{12}{3}+\dfrac{1}{3}=\dfrac{13}{3}\)
\(x^{\frac{13}{3}}\)
Answer: \(x^{\frac{13}{3}}\)
\(x^2\cdot x^{\frac{1}{3}}=x^{2+\frac{1}{3}}\)
\(2=\dfrac{6}{3}\)
\(\dfrac{6}{3}+\dfrac{1}{3}=\dfrac{7}{3}\)
\(x^{\frac{7}{3}}\)
Answer: \(x^{\frac{7}{3}}\)
\(x^5\cdot x^{\frac{1}{2}}=x^{5+\frac{1}{2}}\)
\(5=\dfrac{10}{2}\)
\(\dfrac{10}{2}+\dfrac{1}{2}=\dfrac{11}{2}\)
\(x^{\frac{11}{2}}\)
Answer: \(x^{\frac{11}{2}}\)
\(5x\cdot x^{\frac{1}{3}}=5x^{1+\frac{1}{3}}\)
\(1=\dfrac{3}{3}\)
\(\dfrac{3}{3}+\dfrac{1}{3}=\dfrac{4}{3}\)
\(5x^{\frac{4}{3}}\)
Answer: \(5x^{\frac{4}{3}}\)
Write roots as powers, then subtract the exponents. Keep the coefficient.
The formula is.\(\sqrt[3]{x}=x^{\frac{1}{3}}\)
\(\dfrac{6x}{\sqrt[3]{x}}=\dfrac{6x}{x^{\frac{1}{3}}}\)
The formula is.\(\dfrac{a^m}{a^n}=a^{m-n}\)
\(6x^{1-\frac{1}{3}}\)
\(1=\dfrac{3}{3}\)
\(\dfrac{3}{3}-\dfrac{1}{3}=\dfrac{2}{3}\)
\(6x^{\frac{2}{3}}\)
Answer: \(6x^{\frac{2}{3}}\)
\(\dfrac{x^3}{x^{\frac{1}{2}}}=x^{3-\frac{1}{2}}\)
\(3=\dfrac{6}{2}\)
\(\dfrac{6}{2}-\dfrac{1}{2}=\dfrac{5}{2}\)
\(x^{\frac{5}{2}}\)
Answer: \(x^{\frac{5}{2}}\)
\(\dfrac{2x^2}{x^{\frac{1}{3}}}=2x^{2-\frac{1}{3}}\)
\(2=\dfrac{6}{3}\)
\(\dfrac{6}{3}-\dfrac{1}{3}=\dfrac{5}{3}\)
\(2x^{\frac{5}{3}}\)
Answer: \(2x^{\frac{5}{3}}\)
\(\dfrac{3x^{\frac{1}{2}}}{x^2}=3x^{\frac{1}{2}-2}\)
\(2=\dfrac{4}{2}\)
\(\dfrac{1}{2}-\dfrac{4}{2}=-\dfrac{3}{2}\)
\(3x^{-\frac{3}{2}}\)
Answer: \(3x^{-\frac{3}{2}}\)
\(\sqrt[3]{x^2}=x^{\frac{2}{3}}\)
\(\dfrac{8x}{x^{\frac{2}{3}}}=8x^{1-\frac{2}{3}}\)
\(1=\dfrac{3}{3}\)
\(\dfrac{3}{3}-\dfrac{2}{3}=\dfrac{1}{3}\)
\(8x^{\frac{1}{3}}\)
Answer: \(8x^{\frac{1}{3}}\)
\(\dfrac{1}{5x^{\frac{1}{2}}}=\dfrac{1}{5}\,x^{-\frac{1}{2}}\)
Answer: \(\dfrac{1}{5}x^{-\frac{1}{2}}\)
Two terms, a product of roots, or a power of y written back in x.
The formula is.\(\sqrt[3]{x}=x^{\frac{1}{3}}\)
\(\dfrac{2}{\sqrt[3]{x}}=2x^{-\frac{1}{3}}\)
The formula is.\(\sqrt{x}=x^{\frac{1}{2}}\)
\(5\sqrt{x}=5x^{\frac{1}{2}}\)
\(2x^{-\frac{1}{3}}+5x^{\frac{1}{2}}\)
Answer: \(2x^{-\frac{1}{3}}+5x^{\frac{1}{2}}\)
\(\sqrt[3]{x}=x^{\frac{1}{3}}\)
\(\sqrt[4]{x^3}=x^{\frac{3}{4}}\)
\(x^{\frac{1}{3}}\cdot x^{\frac{3}{4}}=x^{\frac{1}{3}+\frac{3}{4}}\)
\(\dfrac{1}{3}=\dfrac{4}{12}\)
\(\dfrac{3}{4}=\dfrac{9}{12}\)
\(\dfrac{4}{12}+\dfrac{9}{12}=\dfrac{13}{12}\)
\(x^{\frac{13}{12}}\)
Answer: \(x^{\frac{13}{12}}\)
\(\dfrac{1}{3\sqrt{x}}=\dfrac{1}{3}\,x^{-\frac{1}{2}}\)
The formula is.\((ab)^n=a^n b^n\)
\(\left(\dfrac{1}{3}\,x^{-\frac{1}{2}}\right)^2=\dfrac{1}{9}\,x^{-1}\)
Answer: \(\dfrac{1}{9}x^{-1}\)
\(\dfrac{x^2}{x}+\dfrac{\sqrt{x}}{x}\)
\(\dfrac{x^2}{x}=x\)
\(\dfrac{x^{\frac{1}{2}}}{x}=x^{\frac{1}{2}-1}\)
\(1=\dfrac{2}{2}\)
\(\dfrac{1}{2}-\dfrac{2}{2}=-\dfrac{1}{2}\)
\(x^{-\frac{1}{2}}\)
\(x+x^{-\frac{1}{2}}\)
Answer: \(x+x^{-\frac{1}{2}}\)
\(y=8x^{\frac{1}{2}}\)
\(\sqrt[3]{y}=\left(8x^{\frac{1}{2}}\right)^{\frac{1}{3}}\)
The formula is.\((ab)^n=a^n b^n\)
\(8^{\frac{1}{3}}\cdot\left(x^{\frac{1}{2}}\right)^{\frac{1}{3}}\)
\(8^{\frac{1}{3}}=2\)
The formula is.\((a^m)^n=a^{mn}\)
\(x^{\frac{1}{2}\cdot\frac{1}{3}}=x^{\frac{1}{6}}\)
\(2x^{\frac{1}{6}}\)
Answer: \(2x^{\frac{1}{6}}\)
\(y=4x^{-\frac{1}{3}}\)
\(y^3=\left(4x^{-\frac{1}{3}}\right)^3\)
\(4^3\cdot x^{-1}\)
\(64x^{-1}\)
Answer: \(64x^{-1}\)
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