IB AA · Unit 2 · 18B Trigonometric Functions
Rewrite the angle by a full turn, a half turn, or a right angle. The value is sin θ or its opposite.
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Full turns and half turns
sin(θ + 2π) = sin θ
sin(θ − 2π) = sin θ
sin(θ + π) = −sin θ
sin(θ − π) = −sin θ
The angle on the other side
sin(π − θ) = sin θ
sin(2π − θ) = −sin θ
sin(−θ) = −sin θ
A right-angle shift
cos(π2 − θ) = sin θ
cos(θ + π2) = −sin θ
Cosine of a right-angle shift is sine, and the sign follows the quadrant.
A full turn keeps the value. A half turn changes the sign.
sin(θ + 2π) = sin θ
sin(θ + 2π) = 0.42
Answer: 0.42
sin(θ − 2π) = sin θ
sin(θ − 2π) = 0.42
Answer: 0.42
4π = 2 × 2π
sin(θ + 4π) = sin θ
sin(θ + 4π) = 0.42
Answer: 0.42
sin(θ + π) = −sin θ
sin(θ + π) = −0.42
Answer: −0.42
sin(θ − π) = −sin θ
sin(θ − π) = −0.42
Answer: −0.42
3π = π + 2π
sin(θ + 3π) = sin(θ + π)
sin(θ + π) = −sin θ
sin(θ + 3π) = −0.42
Answer: −0.42
sin(π − θ) matches sin θ. A clockwise turn changes the sign.
sin(2π − θ) = −sin θ
sin(2π − θ) = −0.42
Answer: −0.42
sin(π − θ) = sin θ
sin(π − θ) = 0.42
Answer: 0.42
sin(−θ) = −sin θ
sin(−θ) = −0.42
Answer: −0.42
3π − θ = (π − θ) + 2π
sin(3π − θ) = sin(π − θ)
sin(π − θ) = sin θ
sin(3π − θ) = 0.42
Answer: 0.42
sin(−π − θ) = −sin(π + θ)
sin(π + θ) = −sin θ
sin(−π − θ) = sin θ
sin(−π − θ) = 0.42
Answer: 0.42
4π − θ = −θ + 2 × 2π
sin(4π − θ) = sin(−θ)
sin(−θ) = −sin θ
sin(4π − θ) = −0.42
Answer: −0.42
A shift of π/2 turns sine into cosine.
cos(π2 − θ) = sin θ
cos(π2 − θ) = 0.42
Answer: 0.42
cos(θ + π2) = −sin θ
cos(θ + π2) = −0.42
Answer: −0.42
cos(θ − π2) = sin θ
cos(θ − π2) = 0.42
Answer: 0.42
3π2 − θ = π + (π2 − θ)
cos(π + α) = −cos α
cos(3π2 − θ) = −cos(π2 − θ)
cos(π2 − θ) = sin θ
cos(3π2 − θ) = −0.42
Answer: −0.42
θ + 3π2 = (θ + π2) + π
cos(θ + 3π2) = −cos(θ + π2)
cos(θ + π2) = −sin θ
cos(θ + 3π2) = sin θ
cos(θ + 3π2) = 0.42
Answer: 0.42
5π2 − θ = (π2 − θ) + 2π
cos(5π2 − θ) = cos(π2 − θ)
cos(π2 − θ) = sin θ
cos(5π2 − θ) = 0.42
Answer: 0.42
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