IB AA · Unit 2 · 5C Applications of Trigonometry
Use a right triangle for an angle of elevation or depression. Two angles give two equations.
Elevation and depression
An angle of elevation looks up from the horizontal.
An angle of depression looks down from the horizontal.
The right triangle uses the same opposite and adjacent either way.
One triangle
tan θ = oppositeadjacent
Add an eye height or a person’s height only after you have found the height above that eye.
Two angles
When a person moves closer, write a tangent equation from each place.
The difference of the two horizontal distances is the distance walked.
Find the height above the eye first. Add the eye height on the next lines.
tan 28° = height above eyedistance
height above eye = 30 × tan 28°
height above eye = 16.0 m
Total height = 16.0 + 1.60
Total height = 17.6 m
Answer: 17.6 m
tan 22° = height above eyedistance
height above eye = 45 × tan 22°
height above eye = 18.2 m
Answer: 18.2 m
tan 35° = height above eyedistance
height above eye = 18 × tan 35°
height above eye = 12.6 m
Total height = 12.6 + 1.70
Total height = 14.3 m
Answer: 14.3 m
tan 12° = 36distance
distance = 36tan 12°
distance = 169 m
Answer: 169 m
tan 41° = height above eyedistance
height above eye = 25 × tan 41°
height above eye = 21.7 m
Answer: 21.7 m
tan 8° = height above eyedistance
height above eye = 80 × tan 8°
height above eye = 11.2 m
Total height = 11.2 + 2
Total height = 13.2 m
Answer: 13.2 m
Each angle gets its own tangent equation.
tan 32° = h20
h = 20 × tan 32°
h = 12.5 m
Farther distance = 20 + 28 = 48 m
tan θ = 12.548
θ = 14.6°
Answer: 14.6°
tan 27° = h15
h = 15 × tan 27°
h = 7.64 m
Farther distance = 15 + 22 = 37 m
tan θ = 7.6437
θ = 11.7°
Answer: 11.7°
tan 24° = h12
h = 12 × tan 24°
h = 5.34 m
Farther distance = 12 + 18 = 30 m
tan θ = 5.3430
θ = 10.1°
Answer: 10.1°
Height of the bottom above eye level = 3.20 × tan 28°
Bottom = 1.70 m
Height of the top above eye level = 3.20 × tan 47°
Top = 3.43 m
Painting = 3.43 − 1.70
Painting = 1.73 m
Answer: 1.73 m
Height of the bottom above eye level = 2.50 × tan 33°
Bottom = 1.62 m
Height of the top above eye level = 2.50 × tan 58°
Top = 4.00 m
Painting = 4.00 − 1.62
Painting = 2.38 m
Answer: 2.38 m
tan 16° = 11distance
distance = 11tan 16°
distance = 38.4 m
Answer: 38.4 m
The distance walked is the difference of the two adjacent sides.
tan 18° = hx
x = htan 18°
tan 32° = hx − 20
x − 20 = htan 32°
h × 1tan 18° − h × 1tan 32° = 20
h = 201tan 18° − 1tan 32°
h = 13.5 m
Answer: 13.5 m
tan 21° = hx
x = htan 21°
tan 38° = hx − 12
x − 12 = htan 38°
h × 1tan 21° − h × 1tan 38° = 12
h = 121tan 21° − 1tan 38°
h = 9.06 m
Answer: 9.06 m
tan 24° = hx
x = htan 24°
tan 45° = hx − 8
x − 8 = htan 45°
h × 1tan 24° − h × 1tan 45° = 8
h = 81tan 24° − 1tan 45°
h = 6.42 m
Answer: 6.42 m
Distance to the nearer buoy = htan 38°
Distance to the farther buoy = htan 31°
Difference = 16
h = 161tan 31° − 1tan 38°
h = 41.6 m
Answer: 41.6 m
Height of the bottom above eye level = 4.10 × tan 26°
Bottom = 2.00 m
Height of the top above eye level = 4.10 × tan 61°
Top = 7.40 m
Painting = 7.40 − 2.00
Painting = 5.40 m
Answer: 5.40 m
tan 22° = 48distance
distance = 48tan 22°
distance = 119 m
Answer: 119 m
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