IB AI · Unit 2 · 2A Arithmetic Sequences
Substitute the first term and the common difference, then simplify until uₙ is written in terms of n.
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SL 1.2
\(u_n = u_1 + (n-1)d\)
\(S_n = \dfrac{n}{2}\bigl(2u_1 + (n-1)d\bigr)\)
\(S_n = \dfrac{n}{2}(u_1 + u_n)\)
The nth-term formula
\(u_n = u_1 + (n-1)d\)
\(u_n\) = the formula
\(u_1\) = first term
\(n\) = the term number
\(d\) = common difference
Example. \(u_1 = 5\), \(d = 4\). Write a formula for \(u_n\).
\(u_1 = 5\)
\(d = 4\)
\(u_n = 5 + (n-1) \times 4\)
\(u_n = 5 + 4n - 4\)
\(u_n = 4n + 1\)
Substitute, then simplify.
\(u_n = u_1 + (n-1)d\)
\(u_1 = 8\)
\(d = 3\)
\(u_n = 8 + (n-1) \times 3\)
\(u_n = 8 + 3n - 3\)
\(u_n = 3n + 5\)
Answer: \(u_n = 3n + 5\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 7\)
\(d = 3\)
\(u_n = 7 + (n-1) \times 3\)
\(u_n = 7 + 3n - 3\)
\(u_n = 3n + 4\)
Answer: \(u_n = 3n + 4\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 2\)
\(d = 6\)
\(u_n = 2 + (n-1) \times 6\)
\(u_n = 2 + 6n - 6\)
\(u_n = 6n - 4\)
Answer: \(u_n = 6n - 4\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 10\)
\(d = 2\)
\(u_n = 10 + (n-1) \times 2\)
\(u_n = 10 + 2n - 2\)
\(u_n = 2n + 8\)
Answer: \(u_n = 2n + 8\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 15\)
\(d = -3\)
\(u_n = 15 + (n-1) \times \left(-3\right)\)
\(u_n = 15 - 3(n-1)\)
\(u_n = 15 - 3n + 3\)
\(u_n = 18 - 3n\)
Answer: \(u_n = 18 - 3n\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 4\)
\(d = 5\)
\(u_n = 4 + (n-1) \times 5\)
\(u_n = 4 + 5n - 5\)
\(u_n = 5n - 1\)
Answer: \(u_n = 5n - 1\)
Find the first term and the common difference, then the formula.
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 6\)
\(d = 10 - 6\)
\(d = 4\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 6\)
\(d = 4\)
\(u_n = 6 + (n-1) \times 4\)
\(u_n = 6 + 4n - 4\)
\(u_n = 4n + 2\)
Answer: \(u_n = 4n + 2\)
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 3\)
\(d = 8 - 3\)
\(d = 5\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 3\)
\(d = 5\)
\(u_n = 3 + (n-1) \times 5\)
\(u_n = 3 + 5n - 5\)
\(u_n = 5n - 2\)
Answer: \(u_n = 5n - 2\)
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 9\)
\(d = 12 - 9\)
\(d = 3\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 9\)
\(d = 3\)
\(u_n = 9 + (n-1) \times 3\)
\(u_n = 9 + 3n - 3\)
\(u_n = 3n + 6\)
Answer: \(u_n = 3n + 6\)
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 20\)
\(d = 16 - 20\)
\(d = -4\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 20\)
\(d = -4\)
\(u_n = 20 + (n-1) \times \left(-4\right)\)
\(u_n = 20 - 4(n-1)\)
\(u_n = 20 - 4n + 4\)
\(u_n = 24 - 4n\)
Answer: \(u_n = 24 - 4n\)
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 1\)
\(d = 7 - 1\)
\(d = 6\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 1\)
\(d = 6\)
\(u_n = 1 + (n-1) \times 6\)
\(u_n = 1 + 6n - 6\)
\(u_n = 6n - 5\)
Answer: \(u_n = 6n - 5\)
The first term is the first number. The common difference is the jump from one term to the next.
\(u_1 = 8\)
\(d = 11 - 8\)
\(d = 3\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 8\)
\(d = 3\)
\(u_n = 8 + (n-1) \times 3\)
\(u_n = 8 + 3n - 3\)
\(u_n = 3n + 5\)
Answer: \(u_n = 3n + 5\)
Read off the first term and the common difference, then write the formula.
\(u_n = u_1 + (n-1)d\)
\(u_1 = 11\)
\(d = 4\)
\(u_n = 11 + (n-1) \times 4\)
\(u_n = 11 + 4n - 4\)
\(u_n = 4n + 7\)
Answer: \(u_n = 4n + 7\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 6\)
\(d = 5\)
\(u_n = 6 + (n-1) \times 5\)
\(u_n = 6 + 5n - 5\)
\(u_n = 5n + 1\)
Answer: \(u_n = 5n + 1\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 30\)
\(d = -4\)
\(u_n = 30 + (n-1) \times \left(-4\right)\)
\(u_n = 30 - 4(n-1)\)
\(u_n = 30 - 4n + 4\)
\(u_n = 34 - 4n\)
Answer: \(u_n = 34 - 4n\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 2\)
\(d = 9\)
\(u_n = 2 + (n-1) \times 9\)
\(u_n = 2 + 9n - 9\)
\(u_n = 9n - 7\)
Answer: \(u_n = 9n - 7\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 18\)
\(d = -2\)
\(u_n = 18 + (n-1) \times \left(-2\right)\)
\(u_n = 18 - 2(n-1)\)
\(u_n = 18 - 2n + 2\)
\(u_n = 20 - 2n\)
Answer: \(u_n = 20 - 2n\)
\(u_n = u_1 + (n-1)d\)
\(u_1 = 7\)
\(d = 8\)
\(u_n = 7 + (n-1) \times 8\)
\(u_n = 7 + 8n - 8\)
\(u_n = 8n - 1\)
Answer: \(u_n = 8n - 1\)
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