PreCalc 2 · Analytic Trigonometry
Write the angle as a sum or a difference of angles whose sine, cosine, or tangent you know. Then use the formula.
Sum formulas
sin(A + B) = sin A cos B + cos A sin B
cos(A + B) = cos A cos B − sin A sin B
tan(A + B) = tan A + tan B1 − tan A · tan B
Difference formulas
sin(A − B) = sin A cos B − cos A sin B
cos(A − B) = cos A cos B + sin A sin B
tan(A − B) = tan A − tan B1 + tan A · tan B
Exact values
Split the angle into 30°, 45°, or 60°.
75° = 45° + 30°
15° = 45° − 30°
105° = 60° + 45°
A given sine or cosine
Use sin² + cos² = 1 to find the other ratio.
The quadrant tells you the sign.
Then substitute into the sum or difference formula.
Split the angle into 30°, 45°, or 60°.
sin(A + B) = sin A cos B + cos A sin B
A = 45°
B = 30°
sin 45° · cos 30° + cos 45° · sin 30°
sin 45° = 2
cos 30° = 2
cos 45° = 2
sin 30° = 12
sin 45° · cos 30°
4
cos 45° · sin 30°
4
+ 4
Answer: + 4
cos(A + B) = cos A cos B − sin A sin B
A = 45°
B = 30°
cos 45° · cos 30° − sin 45° · sin 30°
cos 45° = 2
cos 30° = 2
sin 45° = 2
sin 30° = 12
cos 45° · cos 30°
4
sin 45° · sin 30°
4
− 4
Answer: − 4
sin(A − B) = sin A cos B − cos A sin B
A = 45°
B = 30°
sin 45° · cos 30° − cos 45° · sin 30°
sin 45° = 2
cos 30° = 2
cos 45° = 2
sin 30° = 12
sin 45° · cos 30°
4
cos 45° · sin 30°
4
− 4
Answer: − 4
cos(A − B) = cos A cos B + sin A sin B
A = 45°
B = 30°
cos 45° · cos 30° + sin 45° · sin 30°
cos 45° = 2
cos 30° = 2
sin 45° = 2
sin 30° = 12
cos 45° · cos 30°
4
sin 45° · sin 30°
4
+ 4
Answer: + 4
tan(A + B) = tan A + tan B1 − tan A · tan B
A = 45°
B = 30°
tan 45° = 1
tan 30° = 3
tan 45° + tan 30°
3 + 3
tan 45° · tan 30°
3
1 − tan A · tan B
3 − 3
2 +
Answer: 2 +
tan(A − B) = tan A − tan B1 + tan A · tan B
A = 45°
B = 30°
tan 45° = 1
tan 30° = 3
tan 45° − tan 30°
3 − 3
tan 45° · tan 30°
3
1 + tan A · tan B
3 + 3
2 −
Answer: 2 −
sin(A + B) = sin A cos B + cos A sin B
A = 60°
B = 45°
sin 60° · cos 45° + cos 60° · sin 45°
sin 60° = 2
cos 45° = 2
cos 60° = 12
sin 45° = 2
sin 60° · cos 45°
4
cos 60° · sin 45°
4
+ 4
Answer: + 4
cos(A + B) = cos A cos B − sin A sin B
A = 60°
B = 45°
cos 60° · cos 45° − sin 60° · sin 45°
cos 60° = 12
cos 45° = 2
sin 60° = 2
sin 45° = 2
cos 60° · cos 45°
4
sin 60° · sin 45°
4
− 4
Answer: − 4
tan(A + B) = tan A + tan B1 − tan A · tan B
A = 60°
B = 45°
tan 60° =
tan 45° = 1
tan 60° + tan 45°
1 +
tan 60° · tan 45°
1 − tan A · tan B
1 −
−(2 + )
Answer: −(2 + )
sin(A + B) = sin A cos B + cos A sin B
A = 2π3
B = π4
sin 2π3 · cos π4 + cos 2π3 · sin π4
sin 2π3 = 2
cos π4 = 2
cos 2π3 = −12
sin π4 = 2
sin 2π3 · cos π4
4
cos 2π3 · sin π4
−4
− 4
Answer: − 4
cos(A + B) = cos A cos B − sin A sin B
A = 2π3
B = π4
cos 2π3 · cos π4 − sin 2π3 · sin π4
cos 2π3 = −12
cos π4 = 2
sin 2π3 = 2
sin π4 = 2
cos 2π3 · cos π4
−4
sin 2π3 · sin π4
4
− + 4
Answer: − + 4
You are given a ratio and a quadrant for each angle.
sin(A + B) = sin A cos B + cos A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 35
sin² A = 925
1 − 925
2525 − 925
1625
cos² A = 1625
A is in Quadrant I, so cosine is positive.
cos A = 45
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = 513
cos² B = 25169
1 − 25169
169169 − 25169
144169
sin² B = 144169
B is in Quadrant I, so sine is positive.
sin B = 1213
sin A · cos B + cos A · sin B
sin A · cos B
35 · 513
1565
313
cos A · sin B
45 · 1213
4865
313 + 4865
1565 + 4865
6365
Answer: 6365
sin(A + B) = sin A cos B + cos A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 45
sin² A = 1625
1 − 1625
2525 − 1625
925
cos² A = 925
A is in Quadrant I, so cosine is positive.
cos A = 35
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = 1213
cos² B = 144169
1 − 144169
169169 − 144169
25169
sin² B = 25169
B is in Quadrant I, so sine is positive.
sin B = 513
sin A · cos B + cos A · sin B
sin A · cos B
45 · 1213
4865
cos A · sin B
35 · 513
1565
313
4865 + 313
4865 + 1565
6365
Answer: 6365
cos(A + B) = cos A cos B − sin A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 513
sin² A = 25169
1 − 25169
169169 − 25169
144169
cos² A = 144169
A is in Quadrant I, so cosine is positive.
cos A = 1213
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = 35
cos² B = 925
1 − 925
2525 − 925
1625
sin² B = 1625
B is in Quadrant I, so sine is positive.
sin B = 45
cos A · cos B − sin A · sin B
cos A · cos B
1213 · 35
3665
sin A · sin B
513 · 45
2065
413
3665 − 413
3665 − 2065
1665
Answer: 1665
sin(A − B) = sin A cos B − cos A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 817
sin² A = 64289
1 − 64289
289289 − 64289
225289
cos² A = 225289
A is in Quadrant I, so cosine is positive.
cos A = 1517
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = 725
cos² B = 49625
1 − 49625
625625 − 49625
576625
sin² B = 576625
B is in Quadrant I, so sine is positive.
sin B = 2425
sin A · cos B − cos A · sin B
sin A · cos B
817 · 725
56425
cos A · sin B
1517 · 2425
360425
7285
56425 − 7285
56425 − 360425
−304425
Answer: −304425
cos(A − B) = cos A cos B + sin A sin B
sin² A + cos² A = 1
sin² A = 1 − cos² A
cos A = 817
cos² A = 64289
1 − 64289
289289 − 64289
225289
sin² A = 225289
A is in Quadrant I, so sine is positive.
sin A = 1517
sin² B + cos² B = 1
cos² B = 1 − sin² B
sin B = 35
sin² B = 925
1 − 925
2525 − 925
1625
cos² B = 1625
B is in Quadrant I, so cosine is positive.
cos B = 45
cos A · cos B + sin A · sin B
cos A · cos B
817 · 45
3285
sin A · sin B
1517 · 35
4585
917
3285 + 917
3285 + 4585
7785
Answer: 7785
tan(A + B) = tan A + tan B1 − tan A · tan B
tan A = 34
tan B = 512
tan A + tan B
34 + 512
912 + 512
1412
76
tan A · tan B
34 · 512
1548
516
1 − tan A · tan B
1 − 516
1616 − 516
1116
761116
76 · 1611
5633
Answer: 5633
sin(A + B) = sin A cos B + cos A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 513
sin² A = 25169
1 − 25169
169169 − 25169
144169
cos² A = 144169
A is in Quadrant II, so cosine is negative.
cos A = −1213
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = 45
cos² B = 1625
1 − 1625
2525 − 1625
925
sin² B = 925
B is in Quadrant I, so sine is positive.
sin B = 35
sin A · cos B + cos A · sin B
sin A · cos B
513 · 45
2065
413
cos A · sin B
(−1213) · 35
−3665
413 − 3665
2065 − 3665
−1665
Answer: −1665
cos(A − B) = cos A cos B + sin A sin B
sin² A + cos² A = 1
sin² A = 1 − cos² A
cos A = −1517
cos² A = 225289
1 − 225289
289289 − 225289
64289
sin² A = 64289
A is in Quadrant II, so sine is positive.
sin A = 817
sin² B + cos² B = 1
cos² B = 1 − sin² B
sin B = −725
sin² B = 49625
1 − 49625
625625 − 49625
576625
cos² B = 576625
B is in Quadrant IV, so cosine is positive.
cos B = 2425
cos A · cos B + sin A · sin B
cos A · cos B
(−1517) · 2425
−360425
−7285
sin A · sin B
817 · (−725)
−56425
−7285 − 56425
−360425 − 56425
−416425
Answer: −416425
tan(A − B) = tan A − tan B1 + tan A · tan B
tan A = 2
tan B = −13
tan A − tan B
2 + 13
63 + 13
73
tan A · tan B
2 · (−13)
−23
1 + tan A · tan B
1 − 23
33 − 23
13
7313
73 · 3
7
Answer: 7
sin(A + B) = sin A cos B + cos A sin B
sin² A + cos² A = 1
cos² A = 1 − sin² A
sin A = 2029
sin² A = 400841
1 − 400841
841841 − 400841
441841
cos² A = 441841
A is in Quadrant I, so cosine is positive.
cos A = 2129
sin² B + cos² B = 1
sin² B = 1 − cos² B
cos B = −35
cos² B = 925
1 − 925
2525 − 925
1625
sin² B = 1625
B is in Quadrant II, so sine is positive.
sin B = 45
sin A · cos B + cos A · sin B
sin A · cos B
2029 · (−35)
−60145
−1229
cos A · sin B
2129 · 45
84145
−1229 + 84145
−60145 + 84145
24145
Answer: 24145
cos(A + B) = cos A cos B − sin A sin B
sin² A + cos² A = 1
sin² A = 1 − cos² A
cos A = −817
cos² A = 64289
1 − 64289
289289 − 64289
225289
sin² A = 225289
A is in Quadrant III, so sine is negative.
sin A = −1517
sin² B + cos² B = 1
cos² B = 1 − sin² B
sin B = −2029
sin² B = 400841
1 − 400841
841841 − 400841
441841
cos² B = 441841
B is in Quadrant IV, so cosine is positive.
cos B = 2129
cos A · cos B − sin A · sin B
cos A · cos B
(−817) · 2129
−168493
sin A · sin B
(−1517) · (−2029)
300493
−168493 − 300493
−468493
Answer: −468493
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