SAT · Algebra
Determine if an equation has one solution, no solution, or infinitely many solutions.
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Tip: Search these exact Question IDs in the College Board SAT Suite Question Bank, Algebra, skill Linear equations in one variable for full questions and rationales.
The variable is already collected. Read the last line.
3x + 2 = 3x + 8
Subtract 3x from both sides.
2 = 8
2 = 8 is a MATH LIE!!
No value of x works.
Answer: no solution
2x + 1 = 7
Subtract 1 from both sides.
2x = 6
x = 3
One solution.
Answer: one solution
5x + 4 = 5x + 4
Subtract 5x from both sides.
4 = 4
4 = 4 is a MATH FACT!!
Every real number is a solution.
Answer: infinitely many solutions
Subtract x from both sides.
3 = 3
3 = 3 is a MATH FACT!!
Answer: infinitely many solutions
4x − 1 = 4x + 2
Subtract 4x from both sides.
−1 = 2
−1 = 2 is a MATH LIE!!
No value of x works.
Answer: no solution
6x − 2 = 10
6x = 12
x = 2
One solution.
Answer: one solution
2(x + 4) = 2x + 8
2x + 8 = 2x + 8
8 = 8
8 = 8 is a MATH FACT!!
Infinitely many solutions.
Answer: infinitely many solutions
3(x − 1) = 3x + 2
3x − 3 = 3x + 2
−3 = 2
−3 = 2 is a MATH LIE!!
No solution.
Answer: no solution
5x − 4 = 2x + 5
Subtract 2x from both sides.
3x − 4 = 5
3x = 9
x = 3
One solution.
Answer: one solution
2x + 6 − x = x + 6
x + 6 = x + 6
6 = 6
6 = 6 is a MATH FACT!!
Infinitely many solutions.
Answer: infinitely many solutions
7 − 3x = 2 − 3x
Add 3x to both sides.
7 = 2
7 = 2 is a MATH LIE!!
No solution.
Answer: no solution
Distribute first, then decide.
4(x − 3) + 2 = 4x − 10
Distribute.
4x − 12 + 2 = 4x − 10
4x − 10 = 4x − 10
Subtract 4x from both sides.
−10 = −10
−10 = −10 is a MATH FACT!!
Every real number works.
Answer: infinitely many solutions
0.5(2x + 8) = x + 5
x + 4 = x + 5
4 = 5
4 = 5 is a MATH LIE!!
No solution.
Answer: no solution
3(2x − 1) − x = 5x − 3
6x − 3 − x = 5x − 3
5x − 3 = 5x − 3
Subtract 5x from both sides.
−3 = −3
−3 = −3 is a MATH FACT!!
Infinitely many solutions.
Answer: infinitely many solutions
2(x + 5) − 3 = 2x + 6
2x + 10 − 3 = 2x + 6
2x + 7 = 2x + 6
7 = 6
7 = 6 is a MATH LIE!!
No solution.
Answer: no solution
5(2x − 3) − 4x = 6x − 14
Distribute.
10x − 15 − 4x = 6x − 14
6x − 15 = 6x − 14
Subtract 6x from both sides.
−15 = −14
−15 = −14 is a MATH LIE!!
No solution.
Answer: no solution
23(6x − 9) − 2x = 2x − 6
4x − 6 − 2x = 2x − 6
2x − 6 = 2x − 6
Subtract 2x from both sides.
−6 = −6
−6 = −6 is a MATH FACT!!
Infinitely many solutions.
Answer: infinitely many solutions
The two sides look different until you simplify.
12(4x − 6) = 2x − 3
2x − 3 = 2x − 3
−3 = −3
−3 = −3 is a MATH FACT!!
Infinitely many solutions.
Answer: infinitely many solutions
24x = 48x
Subtract 24x from both sides.
0 = 24x
Divide both sides by 24.
0 = x
x = 0
Zero is a number, so there is one solution.
Answer: one solution, x = 0
k(x + 2) = 3x + 6
Distribute.
kx + 2k = 3x + 6
Subtract 3x from both sides.
kx − 3x + 2k = 6
x(k − 3) + 2k = 6
If k = 3, then 2(3) = 6, which is 6 = 6, true for every x: infinitely many solutions.
If k ≠ 3, the x term stays, so there is exactly one solution.
The equation has exactly one solution when k ≠ 3.
Answer: k ≠ 3
7x + 4 = px + 4
Subtract 4 from both sides.
7x = px
Subtract px from both sides.
7x − px = 0
x(7 − p) = 0
If p = 7, then 0 = 0, infinitely many solutions.
If p ≠ 7, divide both sides by 7 − p.
x = 0
Zero is a number, so the one solution is x = 0.
Answer: x = 0
21x = 42x
Subtract 21x from both sides.
0 = 21x
Divide both sides by 21.
0 = x
x = 0
Zero is a number, so there is one solution.
Answer: one solution, x = 0
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